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quester [9]
3 years ago
6

 While texting his girlfriend that he was running late for their date, Jordan rear-ended a car stopped at a red light. Since thi

s was clearly an inelastic collision, some of his car's kinetic energy was transformed to other types of energy. What types of energy are most likely to result from such a collision?
Physics
2 answers:
SSSSS [86.1K]3 years ago
5 0
Kinetic energy is the basic energy built in a moving vehicle or object. When the cars impact with another car or object the kinetic energy must be dispersed This is dependent of the speed of the object and the mass.
RideAnS [48]3 years ago
3 0
Heat energy and sound 
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I could tell you the energy if you can tell me the acceleration and height above earth's surface.

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Which of the following is the best example of kinetic energy being transformed into potential energy
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A pendulum is probably the most common showing of this example. As the pendulum swings down, it converts its potential energy (height) into kinetic energy (velocity). At the lowest point the kinetic energy is the highest and the potential is the lowest. At the highest point in its swing the velocity is zero so the kinetic energy is zero and the potential energy is at a maximum (greatest height).

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Light sources send out light waves that_____________.
Crank

Answer:

A. Travel in one direction

Explanation:

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3 years ago
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If two point sources that create circular waves are moved closer together, what happens to the spacing between the nodal and ant
Dennis_Churaev [7]

<span>The distance between the sources of a two point surface interference determines the number of lines that can be created for the nodal and anti-nodal lines. When the sources are moved closer together, the number of lines becomes minimal. Thus, the spaces between the lines become bigger. The answer to this item is letter A. The spacing increases. </span>

8 0
4 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed
kogti [31]

Answer:

a)y_{first}=5.3mm

b)y_{second}=10.6-5.3 =5.3 mm  

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

y=\frac{m\lambda D}{a} when m is a natural number.

here:

  • m is 1 (to find the central bright fringe)                
  • D is the distance from the slit to the screen
  • a is the slit wide
  • λ is the wavelength

So we have:

y_{first}=\frac{633*10^{9}*3.35}{0.0004}

y_{first}=5.3mm

b)

Now, if we do m=2 we can find the distance to the second minima.

y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}

y_{2}=10.6 mm

Now we need to subtract these distance, to get the width of the first bright fringe :

y_{second}=10.6-5.3 =5.3 mm    

I hope it heps you!

     

4 0
3 years ago
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