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bija089 [108]
4 years ago
12

The strongest substance in your body is:

Chemistry
1 answer:
Sholpan [36]4 years ago
3 0
The enamel is the strongest substance in our bodies mainly inside your mouth.
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what are you looking for?

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Because the rock is irregularly shaped, you used the <br> method to measure its volume.
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A physical property can be _________
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color, texture, size

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Density is defined as mass per unit volume, or D = m/v. Solve the density
fgiga [73]

Answer:

v = m/D

Explanation:

<em>Density</em><em> </em><em>is</em><em> </em><em>defined</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>mass</em><em> </em><em>per</em><em> </em><em>unit</em><em> </em><em>volume</em><em>,</em><em> </em><em>or</em><em> </em><em>D</em><em> </em><em>=</em><em> </em><em>m</em><em>/</em><em>v</em><em>.</em><em> </em><em>Solve </em><em>for</em><em> </em><em>Density</em><em> </em><em>equation</em><em> </em><em>for</em><em> </em><em>the </em><em>variable </em><em>v</em><em>:</em>

<em>With</em><em> </em><em>this</em><em> </em><em>we</em><em> </em><em>are</em><em> </em><em>making</em><em> </em><em>v</em><em> </em><em>Which </em><em>represents</em><em> </em><em>volume</em><em> </em><em>the</em><em> </em><em>subject</em><em> </em><em>so</em><em>;</em>

<em>d =  \frac{m}{v}</em>

<em>With</em><em> </em><em>this</em><em> </em><em>you </em><em>multiply</em><em> </em><em>both</em><em> </em><em>sides </em><em>by</em><em> </em><em>;</em>

<em>v</em>

<em>v(d) = ( \frac{m}{v})v</em>

<em>And</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>v</em><em> </em><em>will</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>making</em><em> </em><em>it</em>

<em> </em><em>“</em><em>v</em><em>d</em><em>”</em><em> </em><em>and </em><em>the</em><em> </em><em>‘</em><em>v</em><em>’</em><em> </em><em>will</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>v</em><em> </em><em>making</em><em> </em><em>it</em><em>;</em>

<em>vd = m</em>

<em>So</em><em> </em><em>then </em><em>we</em><em> </em><em>divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>d</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>v</em><em> </em><em>the</em><em> </em><em>subject</em><em>.</em>

<em>\frac{vd}{d} =  \frac{m}{d}</em>

<em>So</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>cancels</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>leaving</em><em>;</em>

<em>v =  \frac{m}{d}</em>

5 0
3 years ago
For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq? A. Keq will increase. B. Keq will dec
Katyanochek1 [597]

B. K_{eq} will decrease.

<h3>Explanation</h3>

The increase in temperature disturbs the equilibrium. The Le Chatelier's Principle suggests that the system would respond in a way that minimizes the degree of the impact.

There's an increase in temperature. The system will try to reduce its temperature. It will favor the backward reaction, which is <em>endothermic </em>and removes heat from the system. Doing so will convert some of its <em>products</em> to <em>reactants</em>.

The K_{eq} of an equilibrium is a fraction of multiple concentrations. For the reversible reaction  a A + b B ⇄ c C + d D, K_{eq} = \frac{[C]^{c}\cdot [D]^d}{[A]^{a} \cdot [B]^{b}}, where [A], [B], [C], and [D] are equilibrium concentrations of the four species. Converting some products back to reactants increases [A] and [B] while reducing [C] and [D]. As a result, K_{eq} will decrease.

4 0
4 years ago
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