The answer is (2) chemical formulas and coefficients. The balanced equation can represent the ratio of mol numbers of reactants and productions. So it is not the mass number counts but the mol number counts.
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9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.
<h3>What is Law of Equivalent ?</h3>
N₁V₁ = N₂V₂
where,
N₁ = Normality of solution with known concentration
V₁ = Volume of solution with known concentration
N₂ = Normality of solution with unknown concentration
V₂ = Volume of solution with unknown concentration
Now find the mass of solution
Mass = Density × Volume
= 1.16 × 0.32 × 1000
= 371.52 g
<h3>How to find the Normality ? </h3>
Normality = ![\frac{\text{Weight}}{\text{Equivalent weight}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BWeight%7D%7D%7B%5Ctext%7BEquivalent%20weight%7D%7D)
= ![\frac{371.52\ g}{36.5}](https://tex.z-dn.net/?f=%5Cfrac%7B371.52%5C%20g%7D%7B36.5%7D)
= 10.18 equivalents
Now put the values in above formula we get
N₁V₁ = N₂V₂
1 × 100 = 10.18 × V₂
100 = 10.18 × V₂
![V_{2} = \frac{100}{10.18}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%5Cfrac%7B100%7D%7B10.18%7D)
= 9.82 mL
Thus from the above conclusion we can say that 9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.
Learn more about the Normality here: brainly.com/question/9754178
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The balanced equation for the reaction is as follows
2RbNO₃ --> 2RbNO₂ + O₂
stoichiometry of RbNO₃ to O₂ is 2:1
number of moles of RbNO₃ decomposed - 5.0 mol
when 2 mol of RbNO₃ decomposes, 1 mol of O₂ is formed
therefore when 5.0 mol of RbNO₃ decomposes - 5.0 / 2 = 2.5 mol of O₂
2.5 mol of O₂ is formed