CF = 5, CD = 12, and EF = 5. Solve for the blanks below:
1 answer:
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0.811 M is the molar concentration of a 252.6 ml aqueous solution prepared with 70.3 g of sugar.
<h3>Define molarity of a solution.</h3>Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Given data:
252.6 mL = 0.2526 L
Next, we shall determine the number of moles of the sugar. This can be obtained as follow:
Molar mass of sugar = 342.30 g/mol.
Mass of sugar = 70.3 g
Mole of sugar =?
Mole =
Mole =
Mole of sugar = 0.205 mole
Finally, we shall determine the molar concentration of the sugar. This can be obtained as follow:
Mole of sugar = 0.205 mole
Volume = 0.2526 L
Molarity =?
Molarity =
Molarity =
Molarity = 0.811 M
Therefore, the molar concentration of the solution is 0.811 M
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