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4 years ago

Which statement explains the method to adjust the strength of the flame on the Bunsen burner?

Chemistry

1 answer:

Anarel [89]4 years ago

4 0

Answer:

adjusting the air mix by rotating the barrel and adjusting the gas with the needle valve to obtain a flame of suitable height and intensity

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Which substance is a heterogeneous mixture

Anton [14]

Mixtures of sand and water or sand and iron filings, a conglomerate rock, water and oil, a portion salad, trail mix, and concrete (not cement).

6 0

4 years ago

Read 2 more answers

Molar mass of c16h19n305s

Masja [62]

Answer:

365.212

Explanation:

According to the given situation, the calculation of molar mass is shown below:-

Data provided

$c_{16}\ h_{19}\ n_3\ o_5\ S$

Molar mass = 16 × 12 + 19 × 1.008 + 3 × 14 + 5 × 16 + 32.06

= 192 + 19.152 + 42 + 80 + 32.06

Molar mass = 365.212

Therefore for determining the molar mass we simply solve the above equation.

So, the correct answer is 365.212

5 0

4 years ago

Which of the following is a strong acid?

Leokris [45]

Answer:

A) HCI( hydrochloric acid)

Explanation:

HCI is a strong acid because it has more number of hydrogen ions whereas acetic acid contains less number of hydrogen ions so its a weak acid

3 0

3 years ago

A compound is found to contain 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen by weight. What is the empirical formula for

insens350 [35]

Answer:

Empirical formula is C₄H₁₀O

Explanation:

Values for C, H and O are determined as centesimal composition.

64.80 g of C in 100g of compound

13.62g of H in 100 g of compound

21.58 g of O in 100 g of compound.

We convert the mass to moles:

64.80 g . 1mol/ 12g = 5.4 moles of C

13.62 g . 1 mol /1g = 13.62 moles of H

21.58 g . 1 mol/16g = 1.35 moles of O

We pick the lowest value and we divide:

5.4 moles of C / 1.35 = 4 C

13.62 moles of H / 1.35 = 10 H

1.35 moles of O / 1.35 = 1 O

Empirical formula is C₄H₁₀O, it can be the diethyl ether.

We confirm, the excersise is well done.

Molar mass = 74g/mol

74 g of compound we have (12 . 4)g of C

In 100 g of compound we may have (100 . 48) / 74 = 64.8 g

5 0

3 years ago

How many carbon atoms are present in a mole of 12C?

kondor19780726 [428]

1 mol of carbon 12 would possess 6.02 X 10^23 carbon atoms.

6 0

3 years ago