For the purpose of proper representation in this item, we let the number of moles of carbon in the compound be x, that of H is y. The equation of toluene now becomes, CxHy The combustion reaction is, CxHy + O2 --> CO2 + H2O
The equation presented above may not be balanced yet. Then, we determine the number of mmols of C, H, and O in the product using the given masses.
(1) 8.20 mg CO2 (8.2 mg CO2)(1 mmol CO2/44 mg CO2) = 0.186 mmol CO2 which means, 0.186 mmol C 0.373 mmol O
(2) 1.92 mg H2O (1.92 mg H2O)(1 mmol H2O/18 mg H2O) = 0.107 mmol H2O which means 0.2133 mmol H 0.107 mmol O
Thus, the equation for toluene is, C(0.186)H(0.2133)
Dividing the numbers by the lesser value, CH(8/7) To eliminate the fraction, we multiply by the denominator. Thus, the final answer would be, <em> C7H8</em>
During diffusion substances move from the denser medium (meaning where there is more of the substance) to less dense medium (meaning where there is less of the substance).
The vertical columns (groups) of the periodic table are arranged such that all its elements have the same number of valence electrons. All elements within a certain group thus share similar properties.
