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Helga [31]
2 years ago
14

Find the relative molecular mass of hydrated iron (II) sulphate FeSO4.7H2O

Chemistry
1 answer:
Pepsi [2]2 years ago
5 0

Answer:

the relative molecular mass of hydrated iron (II) sulfate FeSO4.7H2O is 278.02

Explanation:

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Pachacha [2.7K]

Convert kg into L, then take the moles and divide it by the L of water

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What is the major divide or ridgeline that separate Virginia's watersheds?
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3 years ago
Um átomo X possui 8 neutrons e seu número atômico e igual a 8. Sabendo que esse atomo é isótopos de Y, que possui número de mass
hodyreva [135]
<u>Question in English : </u>
<span>
<em>An atom X has 8 neutrons and its atomic number equals 8. Knowing that this atom is isotopes of Y, which has mass number 18, answer: What is the number of neutrons in atom Y?</em>

</span><span><u>Answer :</u>

</span>

Isotopes are defined as the atoms which have same number of protons but different number of neutrons of same element. Since the proton number is same, the atomic number also same. Hence the atomic number of Y is 8.

Mass number = atomic number + neutron number

                   18 = 8 + neutron number

Neutron number = 10

 

Hence, there are 10 neutrons in Y.

3 0
3 years ago
Briefly discuss interpretations of your observations and results. Include in your discussion, any conclusions drawn from the res
VMariaS [17]

Answer:

In comparison to Part 1 of this experiment, we observed similar reactions when determining the make up of our unknown. When testing for Mn2+ we observed a color change that resulted in a darker brown/red color, when testing for Co2+ we observed the formation of foamy bubbles but we could not conclude that a gas had formed, when testing for Fe3+ the result was a liquid red in color, when testing for Cr3+ we observed no change, when testing for Zn2+ we observed the formation of a pink/red liquid, when testing for K+ we observed the formation of a precipitate, when testing for Ca2+ we observe the formation of a precipitate. Sources of error may have occurred when observing whether or not an actual reaction had taken place or not, using glassware that wasn't fully cleaned, or the accidental mix of various other liquids in the lab

Explanation:

4 0
3 years ago
8. A 15.0 gram unknown piece of metal at 99 oC is added to 75 grams of water at 23 oC. The final temperature of the metal and wa
Setler79 [48]

The specific heat of the unknown metal is 0.859 J/g⁰C.

<h3>Specific heat of the unknown metal</h3>

Heat lost by the unknown metal = Heat gained by water

m₁c₁Δθ₁ = m₂c₂Δθ₂

where;

  • c₁ is specific heat of the unknown metal
  • c₂ is specific heat of water

(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)

1095c₁ = 940.5

c₁ = 940.5/1095

c₁ = 0.859 J/g⁰C

Learn more about specific heat here: brainly.com/question/16559442

#SPJ1

3 0
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