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Anvisha [2.4K]
3 years ago
10

What is formed when two Bromine atoms bond together?

Chemistry
1 answer:
DIA [1.3K]3 years ago
4 0
When two Bromine atoms are joined together, the Bromine molecule is formed and the written formula is Br_{2}
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Q4. The student started with 16.0 grams of NaCl, show the calculation for the percent error that
Vedmedyk [2.9K]

Answer:

72.6% Error

Explanation:

% error = \frac{Real-Measured}{Real} * 100

\frac{58.44-16}{58.44} *100= 72.6

58.44 is the weight of NaCl

5 0
3 years ago
A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b
Dima020 [189]
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
4 0
3 years ago
Element X consist of two isotopes with masses of 62.9 and 64.9. The relative atomic mass of the element is 63.6. What is th
koban [17]

Answer:

it is 50%

Explanation:

62.9x50=3145

64.9x50=3245

3245+3145=6390

6390/100=63.9

4 0
2 years ago
If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

6 0
2 years ago
1.Give an example of a compound machine (1pt). Explain how at least two simple machines are part of this compound machine (2pts)
Law Incorporation [45]
1) An example of a compound machine could be a pair of Scissors. Their are two different simple machines in the Scissors which make up the compound machine. Both of them being a Lever, and a Fulcrum.

Hope this helps!
4 0
2 years ago
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