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jenyasd209 [6]
3 years ago
12

Determine whether the geometric series 25 − 5 + 1 − 0.2 ... converges or diverges, and identify the sum if it exists.

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

Converges

Sum = 20.8333

Step-by-step explanation:

A geometric series has a general formula of:

\sum ar^n

Where 'a' is the initial term, 'n' is the number of terms, and 'r' is the constant ratio. If |r| < 1 than the series converges.

In this particular case, the initial term is a=25, and each term is being divided by -5, or multiplied by -0.2, so the general form would be:

\sum 25*(-0.2)^n

Since 0.2 < 1.0, the series converges.

The sum of the series is given by:

S=\frac{a}{1-r}\\S=\frac{25}{1-(-0.2)}\\S=20.8333

The sum is 20.8333.

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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

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(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Rainbow [258]
P(x) = 2x² - 4xq(x) = x - 3
To find the answer, we plug q(x) into p(x):
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3 years ago
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See attachment file below.

Hope it helped!!

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