What is the area of the figure?

Mathematics

2 answers:

bija089 [108]3 years ago

8 0

Answer:

B)48

Step-by-step explanation:

Cut the figure to get 2 rectangles. 9x4=36 And then 6x2=12. Add the two numbers 36+12 to get 48.

natima [27]3 years ago

8 0

Answer:

48 cm^2

Step-by-step explanation:

We can split this into 2 rectangles

The lower rectangle is 10 by 2

Area = 10*2 = 20 cm^2

The upper rectangle is 9-2 by 10-6 or 7 by 4

A = 7*4 = 28 cm^2

The total area is found by adding the areas together

A = 20 + 28 = 48 cm^2

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At which values of x does the function F(x) have a vertical asymptote? Check

Vaselesa [24]

Answer:

x=0, x= - 3, x=9

Step-by-step explanation:

f(x)=7/2x(x+3)(x-9)

f(x) doesn't exist for x=0,-3,9

$\lim_{x \to \ 0,-3,9} f(x) = inf$

vertical asymptote:

x=0, x= - 3, x=9

3 0

3 years ago

A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible

steposvetlana [31]

Answer:

$AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

$AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}$

BA is:

$BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$