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Marianna [84]
3 years ago
15

What is the scale factor?

Mathematics
2 answers:
erastova [34]3 years ago
6 0

Answer:

4

Step-by-step explanation:

2 x  4 = 8

4 x 4 = 16

So SF = 4 (enlargement)

KengaRu [80]3 years ago
4 0
Scale factor in this question is 4
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How does the graph of f(x) = (x − 9)4 − 3 compare to the parent function g(x) = x4?
Paraphin [41]

Answer:

The graph is shifted right by 9 units and down by 3 units

Step-by-step explanation:

8 0
3 years ago
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PLEASE HELP!! i cant figure out how to do it
vodomira [7]

Answer:

168 and 12

Step-by-step explanation:

use fractions for this think of it as 14/15x and 1/15x and x is 180 and solve from there

3 0
2 years ago
Ms. Clint is comparing the sales of sweaters and gloves at her store for the past ten winter weeks. Select the true statement ba
lianna [129]

Answer:

i would say b

Step-by-step explanation:

6 0
3 years ago
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Need help with this asap!
Brums [2.3K]

Answer:

The answer to your question is   b = 8.06 cm

Step-by-step explanation:

Data

hypotenuse = c = 9 cm

long leg = b = ?

short leg = a = 4 cm

Process

This is a right triangle so we must use the Pythagorean theorem to find the length of the long leg (b)

                      c² = a² + b²

-Solve for b²

                      b² = c² - a²

-Substitution

                      b² = 9² - 4²

-Simplification

                       b² = 81 - 16

                       b² = 65

-Result

                      b = 8.06 cm

4 0
3 years ago
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Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand
dybincka [34]

Answer: Part a) P(a)=\frac{1}{\binom{r+w}{r}}

part b)P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = P(E)=\frac{Favourablecases}{TotalCases}

For part a)

Probability that a red ball is drawn in first attempt = P(E_{1})=\frac{r}{r+w}

Probability that a red ball is drawn in second attempt=P(E_{2})=\frac{r-1}{r+w-1}

Probability that a red ball is drawn in third attempt = P(E_{3})=\frac{r-2}{r+w-1}

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = P(E_{i})=\frac{r-i}{r+w-i}

Thus the probability that events E_{1},E_{2}....E_{i} occur in succession is

P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...

Thus P(E)=\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!

Thus our probability becomes

P(E)=\frac{1}{\binom{r+w}{r}}

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at (r+1)^{th} draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals \binom{r}{r-1}

Thus the probability becomes P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}

Thus required probability of case b becomes P(E)+ P(E_{i})

= P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\

7 0
3 years ago
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