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Sonja [21]
2 years ago
5

Another carbon isotope has six protons and seven neutrons in its nucleus. What do you think this carbon isotope is called?

Chemistry
2 answers:
insens350 [35]2 years ago
8 0

Answer:

Carbon - 13

Explanation:

For most of the elements other than that of hydrogen, the isotopes are named for the mass number.

Example : Carbon atoms with 6 neutrons have mass number of 12 ( as 6\ protons +6\ neutrons=12 ), so they are known as carbon-12.

Given that:

Protons = 6

Neutrons = 7

Mass = 6 + 7 = 13

So the name is Carbon - 13 . The symbol is ^{13}_{6}C

Bas_tet [7]2 years ago
6 0

Answer: C-13 isotope

Explanation:

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons

For carbon : number of protons = 6

number of neutrons = 7

Thus Atomic number = 6

Mass number = 7+ 6= 13

Thus isotope is called as carbon-13 isotope.

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The oxygen atom is smaller than the sulfur atom because _____(1) the outer electrons of oxygen are more effectively screened fro
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Answer: Option (2) is the correct answer.

Explanation:

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3 0
3 years ago
Which statement is true for nuclear reactions but not for chemical reactions?
IrinaVladis [17]

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Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

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