<u>Answer:</u> The final pressure of the gas is 9.41 atm
<u>Explanation:</u>
To calculate the pressure of the gas, we use the equation given by ideal gas equation:
where,
P = pressure of the gas = ?
V = Volume of gas = 
(Conversion factor: 
)
n = Number of moles = 0.01 mol
R = Gas constant = 
T = temperature of the gas = ![300^oC=[300+273]K=573K](https://tex.z-dn.net/?f=300%5EoC%3D%5B300%2B273%5DK%3D573K)
Putting values in above equation, we get:
Hence, the final pressure of the gas is 9.41 atm
27.6 - 22.3 = 5.3; you simply subtract the old density from the new density.
Answer:
n = 2.58 mol
Explanation:
Given data:
Number of moles of argon = ?
Volume occupy = 58 L
Temperature = 273.15 K
Pressure = 1 atm
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 58 L = n × 0.0821 atm.L/ mol.K × 273.15 K
58 atm.L = n × 22.43 atm.L/ mol.
n = 58 atm.L / 22.43 atm.L/ mol
n = 2.58 mol
