The statement was false as it mentioned, the profit-maximizing rule leaves room for cases where it is both possible and reasonable for a firm to operate at a loss over the long run
What is profit-maximizing rule ?
According to the Profit Maximization Rule, if a corporation want to maximise its profits, it must select the level of output where Marginal Cost (MC) equals Marginal Revenue (MR) and the Marginal Cost curve is increasing. To put it another way, it must generate at a level where MC = MR.
The profit maximization rule formula is as follows:
MC = MR
The marginal cost is the cost increase caused by manufacturing one extra unit of an item.
The difference in total revenue as a result of altering the rate of sales by one unit is referred to as marginal revenue. The slope of Total Revenue is also known as Marginal Revenue.
Total Revenue - Total Costs = Profit
Profit maximisation happens when there is a considerable gap or disparity between total revenue and total cost.
so the given statement the profit-maximizing rule leaves room for cases where it is both possible and reasonable for a firm to operate at a loss over the long run. was a false statement.
To learn more about profit-maximizing rule follow the given link: brainly.com/question/7586794
#SPJ4
Answer:
(b) lose electrons and form positive ions
Explanation:
<u>Ionic bonding:-
</u>
This type of bonding is formed when there is a complete transfer of electrons from one element to another element. In this bonding one element is always a metal and another is a non-metal.
<u>For example, the formation of NaCl</u>
The electronic configuration of sodium with Z = 11 is : 2, 8, 1
The electronic configuration of chlorine with Z = 17 is : 2, 8, 7
<u>Thus, sodium loses one electron and become positively charged and chlorine accepts this electron and become negatively charged and they have both their octets complete and form ionic bond.</u>
Hence, can be seen from the above example, metallic atoms generally lose electrons and form positive ions.
The balanced reaction that describes the reaction between methane and oxygen to produce water and carbon dioxide is expressed CH4 + 2 O2 = CO2 +2H2O. Hence for 2 moles of methane used, 4 moles of oxygen are needed to react completely.
Answer : The value of
for
is
.
Solution : Given,
Solubility of
in water = ![4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.
The equilibrium equation is,
![BaCO_3\rightleftharpoons Ba^{2+}+CO^{2-}_3](https://tex.z-dn.net/?f=BaCO_3%5Crightleftharpoons%20Ba%5E%7B2%2B%7D%2BCO%5E%7B2-%7D_3)
Initially - 0 0
At equilibrium - s s
The Solubility product will be equal to,
![K_{sp}=[Ba^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)
![K_{sp}=s\times s=s^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3Ds%5Ctimes%20s%3Ds%5E2)
![[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%3D%5BCO%5E%7B2-%7D_3%5D%3Ds%3D4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
Now put all the given values in this expression, we get the value of solubility constant.
![K_{sp}=(4.4\times 10^{-5}mole/L)^2=19.36\times 10^{-10}mole^2/L^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%284.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL%29%5E2%3D19.36%5Ctimes%2010%5E%7B-10%7Dmole%5E2%2FL%5E2)
Therefore, the value of
for
is
.
Answer:
Explanation:
I’m pretty sure that stories differ because they are not proven and can be easily manipulated. Scientific explanations are proven and are probably fact.