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Wewaii [24]
4 years ago
16

Which would be best suited to form a circuit?

Chemistry
2 answers:
iogann1982 [59]4 years ago
8 0
Metal Wire would best be suited
ANTONII [103]4 years ago
8 0
The metal wire is the most common and the best material
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Two students prepare lab reports one for a chemistry class and the other for a biology class which of the following items will b
AleksandrR [38]

Answer:

the results of an investigation thank me later

Explanation:

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John finds a rock that contains large, light-colored mineral crystals. the rock shows no sign of being altered by heat or pressu
cupoosta [38]

From the above statement, John can infer that the rock underwent metamorphism and also is not altered by heat or pressure.

<u>Explanation</u>:

  • Metamorphic rock is an igneous sedimentary rock and although when put through heat the rock becomes hot but does not alter its shape or melt. If the rock melts then it is only an igneous rock and not a sedimentary one.
  • During metamorphism, the chemical and the mineral content of prolith are changed due to changes in the environment based on physical and chemical conditions.
  • Even though the rocks remain solid, fluid is present between the macroscopic spaces.
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3 years ago
Which choice is an example of producer<br> A. Sun<br> B. Tree <br> C. Water<br> D. Bird
valina [46]
Sun. The sun is the producer because it is producing energy and sunlight for the organisms living on Earth
6 0
3 years ago
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Identify the process being described by each sentence.
lana [24]
1.melting
2.freezing
3.condensation
4. evaporation
5.sublimation
5 0
3 years ago
A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
Tasya [4]

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

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