Question

Methylhydrazine, CH6N2, is commonly used as a liquid rocket fuel. The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mol. How much heat is released when 202.7 g of methylhydrazine is burned

Answer 1

Answer:

There is 5720 J of heat released.

Explanation:

Step 1: Data given

Molar mass of CH6N2 = 46.07 g/mol

The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mol

Mass of methylhydrazine = 202.7 grams

Step 2: Calculate number of moles

Moles CH6N2 = mass of CH6N2 / Molar mass CH6N2

Moles CH6N2 = 202.7 grams / 46.07 g/mol

Moles CH6N2 = 4.4 moles

Step 3: Calculate heat released when 202.7 grams of CH6N2 is burned

q = 1300 J/mol * 4.4 moles

q = 5720 J

(Since there is heat released, ΔH = negative)

There is 5720 J released.