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Harman [31]
3 years ago
9

Methylhydrazine, CH6N2, is commonly used as a liquid rocket fuel. The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mo

l. How much heat is released when 202.7 g of methylhydrazine is burned
Chemistry
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

There is 5720 J of heat released.

Explanation:

Step 1: Data given

Molar mass of CH6N2 = 46.07 g/mol

The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mol

Mass of methylhydrazine = 202.7 grams

Step 2: Calculate number of moles

Moles CH6N2 = mass of CH6N2 / Molar mass CH6N2

Moles CH6N2 = 202.7 grams / 46.07 g/mol

Moles CH6N2 = 4.4 moles

Step 3: Calculate heat released when 202.7 grams of CH6N2 is burned

q = 1300 J/mol * 4.4 moles

q = 5720 J

(Since there is heat released, ΔH = negative)

There is 5720 J released.

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2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

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from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

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number of moles = \frac{mass}{atomic mass of 1 mole}

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3 0
3 years ago
2. A sample of oxygen gas is placed in a rigid 1.5L glass container at STP. If the gas is
sladkih [1.3K]

The new pressure : P₂ = 1038.39 mmHg

<h3>Further explanation</h3>

Given

1.5 L container at STP

Heated to 100 °C

Required

The new pressure

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure).

So P₁ =  1 atm = 760 mmHg

T₁ = 273 K

T₂ = 100 °C+273 = 373 K

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Input the value :

P₂=(P₁.T₂)/T₁

P₂=(760 x 373)/273

P₂ = 1038.39 mmHg

7 0
3 years ago
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