Answer:
109.09°C
Explanation:
Given that:
the capacity of the cooling car system = 5.6 gal
volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.
∴ 
Afterwards, the mass of the solute and the mass of the water can be determined as shown below:
mass of solute = 
On the other hand; the mass of water = 
Molarity = 
= 
= 17.757 m
≅ 17.76 m
∴ the boiling point of the solution is calculated using the boiling‑point elevation constant for water and the Molarity.
where,
= 0.512 °C/m
= 100°C + 17.56 × 0.512
= 109.09 °C
Answer is: the average atomic mass is 232.
ω₁ = 20% ÷ 100%.
ω₁ = 0.20.
ω₂ = 80% ÷ 100%.
ω₂ = 0.80.
Ar₁ = 120 (number of protons) + 120 (number of neutrons).
Ar₁ = 240.
Ar₂ = 120 + 110
.
Ar₂ = 230.
Average atomic mass of atoms of bolognium =
Ar₁ · ω₁ + Ar₂ · ω₂.
Average atomic mass of atoms of bolognium = 240 · 0.2 + 230 · 0.8.
Average atomic mass of atoms of bolognium = 48 + 184.
Average atomic mass of atoms of bolognium = 232.
Answer:
Mass = 114.26 g
Explanation:
Given data:
Number of gold atoms = 3.47×10²³ atoms
Mass in gram = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
3.47×10²³ atoms × 1 mol /6.022 × 10²³ atoms
0.58 mol
Mass of gold:
Mass = number of moles × molar mass
Mass = 0.58 mol × 197 g/mol
Mass = 114.26 g
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