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grigory [225]
3 years ago
6

Describe an E2 mechanism

Engineering
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

The answer is C): Stereospecific and concerted.

Explanation:

An E2 mechanism is a single step elimination reaction that is both stereospecific and concerted: it is stereospecific because it can convert the components of the reaction into stereoisomeric products; it is concerted because all bonds are broken and formed during the single step.

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Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow
Black_prince [1.1K]

Answer:

\omega_y,\omega_x,\omega_Z  all are zero.

Explanation:

We know that if flow is possible then it will satisfy the below equation

\dfrac{\partial u}{\partial x}+\dfrac{\partial v}{\partial y}+\dfrac{\partial w}{\partial z}=0

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function \phi given as follows

 u=-\frac{\partial \phi }{\partial x},v=-\frac{\partial \phi }{\partial y},w=-\frac{\partial \phi }{\partial z}

Rotationality of fluid is given by \omega

\frac{\partial v}{\partial x}-\frac{\partial u}{\partial y}=\omega_Z

\frac{\partial v}{\partial z}-\frac{\partial w}{\partial y}=\omega_x

\frac{\partial w}{\partial x}-\frac{\partial u}{\partial z}=\omega_y

So now putting value in the above equations ,we will find

\omega =\frac{\partial \phi }{\partial x},u=\frac{\partial \phi }{\partial x},

\omega_y=\dfrac{\partial^2 \phi }{\partial z\partial x}-\dfrac{\partial^2 \phi }{\partial z\partial x}

So \omega_y=0

Like this all \omega_y,\omega_x,\omega_Z all are zero.

That is why  velocity potential flow is irroational flow.

5 0
4 years ago
Using the Distortion-Energy failure theory: 8. (5 pts) Calculate the hydrostatic and distortional components of the stress 9. (1
WITCHER [35]

Answer:

Detailed solution is given below:

7 0
4 years ago
Explain why the scenario below fails to illustrate an understanding of the importance of metrology. Situation: Natalie is a cali
VMariaS [17]

Answer:

Explanation:

The situation being described completely fails in regard to the importance of metrology. This is because the main importance of metrology is making sure that all of the measurements in a process are as accurate as possible. This accuracy allows an entire process to function efficiently and without errors. In a food production plant, each individual department of the plant relies on the previous function to have completed their job with the correct and accurate instructions so that they can fulfill their functions correctly and end up with a perfect product. If the oven (like in this scenario) is a couple of degrees off it can cause the product to come out burned or undercooked, which will then get transferred to the next part of production which will also fail due to the failed input (burned or undercooked product). This will ultimately lead to an unusable product at the end of the process and money wasted. Which in a large production plant means thousands of products in a single batch are thrown away.

8 0
3 years ago
The force of T = 20 N is applied to the cord of negligible mass. Determine the angular velocity of the 20-kg wheel when it has r
horrorfan [7]

Image of wheel is missing, so i attached it.

Answer:

ω = 14.95 rad/s

Explanation:

We are given;

Mass of wheel; m = 20kg

T = 20 N

k_o = 0.3 m

Since the wheel starts from rest, T1 = 0.

The mass moment of inertia of the wheel about point O is;

I_o = m(k_o)²

I_o = 20 * (0.3)²

I_o = 1.8 kg.m²

So, T2 = ½•I_o•ω²

T2 = ½ × 1.8 × ω²

T2 = 0.9ω²

Looking at the image of the wheel, it's clear that only T does the work.

Thus, distance is;

s_t = θr

Since 4 revolutions,

s_t = 4(2π) × 0.4

s_t = 3.2π

So, Energy expended = Force x Distance

Wt = T x s_t = 20 × 3.2π = 64π J

Using principle of work-energy, we have;

T1 + W = T2

Plugging in the relevant values, we have;

0 + 64π = 0.9ω²

0.9ω² = 64π

ω² = 64π/0.9

ω = √64π/0.9

ω = 14.95 rad/s

4 0
4 years ago
Viscous effects are negligible outside of the hydrodynamic boundary layer. (3 points) a. True b. False
Valentin [98]

Answer:

I would say false but I am not for sure

8 0
3 years ago
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