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Brrunno [24]
3 years ago
13

Real-world examples of power

Physics
1 answer:
Paha777 [63]3 years ago
3 0
By definition, power is the amount of energy consumed (or produced) in a second. (or more precisely, it is the rate of change in energy).
so anything which uses energy in a known time period can be labeled with a power rating.

an example for power could be a nuclear plant; traditional nuclear plants produce somewhat close to 1 giga watts (which means 1 giga joules in a second)


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A gas had a initial volume of 168 cm at a temperature of 255 k and a pressure of 1.6 atm the pressure of the gas decreased to 1.
Mademuasel [1]

P₁V₁ / T₁ = P₂V₂ / T₂

1.6 × 168 /255 = 1.3 × V₂ / 285

V₂ = 1.6 × 168 × 285 / (1.3 × 255)

V₂ = 231.095

The final volume = 231 cm³

7 0
3 years ago
The red light emitted by a helium–neon laser has a wavelength of 632.8 nm. What is the frequency of the light waves?
Monica [59]

f = 4.74 × 10 ^14  Hz

hope this helps:)

5 0
3 years ago
5. A bicyclist is finishing her repair of a flat tire when a friend rides by at a constant velocity of
FrozenT [24]

Answer:

a) t = 3.6 s

b) d = 23 m

c) v = 13 m/s

Explanation:

Let t be the time the accelerating rider rides

the distance she travels is

d = ½3.6t²

the distance for the other cyclist is

d =3.5(t + 3)

½3.6t² = 3.5(t + 3)

1.8t² - 3.5t - 10.5 = 0

quadratic formula, positive answer

t = (3.5 + √(3.5² - 4(1.8)(-10.5))) / (2(1.8))

t = 3.575786...

d = ½(3.6)(3.575786²) = 23.015...

v = 3.6(3.575786) = 12.8728...

8 0
2 years ago
Suppose the B string on a guitar is 24" long and vibrates with a frequency of about 247 Hz. You place your finger on the 5th fre
pashok25 [27]

To solve this problem it is necessary to apply the related concepts to string vibration. This concept shows the fundamental frequency of a string due to speed and length, that is,

f = \frac{v}{2L}

Where

v = Velocity

L = Length

Directly if the speed is maintained the frequency is inversely proportional to the Length:

f \propto \frac{1}{L}

Therefore the relationship between two frequencies can be described as

\frac{f_2}{f_1}=\frac{l_1}{l_2}

f_2 = \frac{l_1}{l_2}(f_1)

Our values are given as,

l_1 = 24"\\f_1 = 247Hz\\l_2 = 18"

Therefore the second frequency is

f_2 = \frac{l_1}{l_2}(f_1)\\f_2 = \frac{24}{18}(247)\\f_2 = 329.33Hz

The frequency allocation of 329Hz is note E.

8 0
3 years ago
Sigh someone stole the points and it marked as an answer so please someone actually answer this.
lbvjy [14]

Answer:

Hope this solution helps you

7 0
3 years ago
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