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Maru [420]
3 years ago
14

A gumball machine has 200 red gum balls. if the red gumballs are 50% of the total number of gum balls, how many gumballs are in

the gum ball machine
Mathematics
2 answers:
galina1969 [7]3 years ago
6 0
400 gumball are in the machine. It's 400 gumballs because 50% is half and 200 is half of 400.
lbvjy [14]3 years ago
4 0
400 are in it 200x2 = 400

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Which of the following are the appropriate LaTeX: f\left(x\right)f ( x ) and LaTeX: g\left(x\right)g ( x ), for LaTeX: H\left(x\
katen-ka-za [31]

Answer:

f\left(x\right)=\cos\left(x\right)\: and\:\: g\left(x\right)=\left(2x^2-1\right)

Step-by-step explanation:

We have, H\left(x\right)=\cos\left(2x^2-1\right)H ( x )

                          =\cos\left(2x^2-1\right)

And   H\left(x\right)=\left(f\:\circ\:g\right)\left(x\right)H ( x ) = \left(f\:\circ\:g\right)( x )

        \Rightarrow \left(f\:\circ\:g\right)(x)=\cos\left(2x^2-1\right)

Now, f\left(x\right)=\cos\left(x\right)   and g\left(x\right)=\left(2x^2-1\right)

     

5 0
3 years ago
For the function f(x) = (5-6x)^2, fine f^-1
Scorpion4ik [409]

Answer:

f(-1) = 121

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f(x) = (5-6x)^2 (First we will substitute x for -1)

f(-1) = (5-6(-1))^2 (Then we will combine like terms)

f(-1) = (11)^2 (Then we will square it)

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8 0
3 years ago
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
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eduard
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Artemon [7]
A) 5

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3 0
3 years ago
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