Question

A solution of sucrose in water is 48.5% sucrose by mass and has a density of 1.118 g/ml. what mass of sucrose, in grams, is contained in 3.50 l of solution?

Answer 1

To determine the mass of sucrose from a given volume of solution, we need to convert the volume into mass by using the density of the solution. We calculate as follows:

mass solution = 3.50 ( 1118 ) = 3913 g

mass of sucrose = 3913 g solution ( .485 g sucrose / g solution ) = 1897.805 g sucrose is present in the solution.

Answer 2

Answer: The mass of sucrose in the given volume of solution is 1897.92 grams.

Explanation:

We are given:

Mass percent of sucrose is 48.5 %. This means that 48.5 grams of sucrose is present in 100 grams of solution.

Density of solution = 1.118 g/mL

To calculate volume of a substance, we use the equation:

$Density=\frac{Mass}{Volume}$

Putting values in above equation, we get:

$1.118g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=89.44mL$

We need to find the mass of sucrose present in 3.50 L or 3500 mL of solution, we apply unitary method:

In 89.44 mL of volume, the mass of sucrose present is 48.5 grams.

So, in 3500 mL of solution, the mass of sucrose present will be $\frac{48.5g}{89.44mL}\times 3500mL=1897.92g$

Hence, the mass of sucrose in the given volume of solution is 1897.92 grams.