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Pavlova-9 [17]
2 years ago
10

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

s celsius . During the reaction 69.0kJ of heat flows out of the bath and into the flask.
Required:
Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J*g*K. Round your answer to 3 significant digits.
Chemistry
1 answer:
Lena [83]2 years ago
5 0

Answer:

T_F=31.9^0C

Explanation:

Hello,

In this case, the energy content is modeled via:

Q=mCp(T_F-T_0)

Since the unknown is the final temperature, it is solved by:

T_F=T_0+\frac{Q}{mCp} =33.9^0C+\frac{-69.0kJ}{8.10kg*4.18\frac{kJ}{kg*^0C}} \\T_F=31.9^0C

The heat is negative since it flows out of the bath that is the considered system.

Best regards.

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You are given an unknown gaseous binary compound (that is, a compound consisting of two different elements). when 10.0 g of the
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Answer is: a possible identity for the unknown compound is C₃H₈.

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M(binary compound) = 1.38 · 32 g/mol.

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n(binary compound) = 10 g ÷ 44.16 g/mol.

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Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.

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8 0
3 years ago
How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?
aksik [14]

Complete Question:

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride. How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?

Answer:

2.23x10⁶ g

Explanation:

The concentration of the fluoride (F⁻) must be 0.800 ppm, which is 0.800 parts per million, so the water must have 0.800 g of F⁻/ 1000000 g of the solution. The density of the water at room temperature is 997 kg/m³ = 997x10³ g/m³. So, the concentration of the fluoride will be:

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The volume of the reservoir is the volume of the cylinder: area of the base * depth. The base is a circumference, which has an area:

A = πR², where R is the radius = 1.01x10² m (half of the diameter)

A = π*(1.01x10²)²

A = 32047 m²

The volume is then:

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m = 2.23x10⁶ g

8 0
3 years ago
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