Answer:
a) F = 3.2 10⁻¹⁰ N
, b) v = 9.9 10⁷ m / s
Explanation:
a) The electric force is
F = q E
The electric field is related to the potential reference
V = E d
E = V / d
Let's replace
F = e V / d
Let's calculate
F = 1.6 10⁻¹⁹ 28 10³ / 1.4 10⁻²
F = 3.2 10⁻¹⁰ N
b) For this part we can use kinematics
v² = v₀ + 2 a d
v = √ 2 ad
Acceleration can be found with Newton's second law
e V / d = m a
a = e / m V / d
a = 1.6 10⁻¹⁹ / 9.1 10⁻³¹ 28 10³ / 1.4 10⁻²
a = 3,516 10⁻¹⁷ m / s²
Let's calculate the speed
v = √ (2 3,516 10¹⁷ 1.4 10⁻²)
v = √ (98,448 10¹⁴)
v = 9.9 10⁷ m / s
Answer:
L = 2.8 cm
Explanation:
Period T = 4 / 12 = 1/3 s
T = 2π√(L/g)
L = (T/2π)²g
L = ((1/3)/2π)²9.8 = 0.02758... ≈ 2.8 cm
Answer:
The angular velocity is 
Explanation:
From the question we are told that
The mass of each astronauts is 
The initial distance between the two astronauts 
Generally the radius is mathematically represented as 
The initial angular velocity is 
The distance between the two astronauts after the rope is pulled is 
Generally the radius is mathematically represented as 
Generally from the law of angular momentum conservation we have that
Here 
is the initial moment of inertia of the first astronauts which is equal to 
the initial moment of inertia of the second astronauts So
Also 
is the initial angular velocity of the first astronauts which is equal to 
the initial angular velocity of the second astronauts So
Here 
is the final moment of inertia of the first astronauts which is equal to 
the final moment of inertia of the second astronauts So
Also 
is the final angular velocity of the first astronauts which is equal to 
the final angular velocity of the second astronauts So
So
=> 
=> 
=> 
=>
Answer:
37.33m
Explanation:
Using the equation of motion
S = ut + 1/2gt^2
Time t = 2.76secs
g = 9.8m/s^2
S = 0 + 1/2(9.8)(2.76)^2
S = 4.9*7.6176
S = 37.33
Hence the window is 37.33m above the ground
