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tatyana61 [14]
3 years ago
8

If a piece of space debris is too large to be a meteoroid and too small to be a planet, it could be

Physics
2 answers:
rewona [7]3 years ago
8 0

The answer is B. an asteroid

Vaselesa [24]3 years ago
3 0

an asteroid was the correct answer


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What is the definition of Rock Strata and Law of Original Horizontality?
timurjin [86]
It's called the <span>Principle of Original Horizontality
</span><span> it just </span>means<span> what it sounds like: that all </span>rock layers <span>were originally horizontal.
</span>Of course, it only applies to sedimentary rocks<span>.
</span>Recall that sedimentary rock is composed of <span> sediments, which are deposited and compacted in one place over time.</span>
3 0
3 years ago
032. A 25.0 kg bicycle is traveling at a speed of 10.0 m/s.
dimulka [17.4K]
Answer:
A: 4
B: 7
C. 3
Source:
Trust me bro
(Don’t act put this I jus need to answer questions sorry)<\3
7 0
2 years ago
A pot on the stove contains 200 g of water at 20°C. An unknown mass of ice that is originally at −10°C is placed in an identical
Mumz [18]

Answer:

a) The mass of the ice is smaller than the mass of the water

b) The ice reaches first 80°C ,

Explanation:

Since the heat Q that should be provided to ice

Q = sensible heat to equilibrium temperature (as ice) + latent heat + sensible heat until final temperature ( as water)

m ice * c ice * ( T equil -T initial  ) + m ice* L + m ice* c water * ( T final - T equil)

and the heat Q that should be provided to water is

Q= m water * c water * ( T final - T equil )

since the rate of heat addition q = constant and the time t taken to reach the final temperature is the same , then the heat absorbed Q=q*t is the same for both, therefore

m water * c water *  ( T final - T equil ) = m ice* [c ice *( T equil -T initial  ) + L + c water * ( T final - T equil)]

m water/ m ice =  [c ice * ( T equil -T initial  )  + L + c water * ( T final - T equil)]/ [ c water * ( T final - T equil)]

m water/ m ice = [c ice * ( T equil -T initial  )  + L ]/[c water * ( T final - T equil) ] + 1

since  [c ice * ( T equil -T initial  )  + L ]/[c water * ( T final - T equil) ] >0 , then

m water/ m ice > 1

m water > m ice

so the mass of ice is smaller that the mass of water

b) Since the heat Q that should be provided to the ice, starting from 55°C mass would be

Q ice= m ice * c water * ( T final2 - T final1 )

and for the water mass

Q water = m water * c water * ( T final2 - T final1 )

dividing both equations

Q water / Q ice = m water / m ice >1

thus

Q water > Q ice

since the heat addition rate is constant

Q water = q* t water and Q ice=q* t ice

therefore

q* t water > q* t ice

t water >  t ice

so the time that takes to reach 80°C is higher for water , thus the ice mass reaches it first.

5 0
3 years ago
Can anybody write a short poem about friction
Luden [163]
Answer:

you will be the clouds
and I will be the sky.
you will be the ocean
and I will be the shore.
you will be the trees
and I will be the wind.

whatever we are, you and I will always collide.

There you go! Let me know if it helped.
:)
8 0
2 years ago
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
Paladinen [302]
1 m = 1 000 000 ym

converted other way we can say that:

1 ym = 10^{-6} m

Now, since we have ym^2 which is ym*ym which means:
1 ym^2 = (10^{-6}) ^2  =  10^{-12} m

we have 1,5 ym^2 which means that answer is:
1.5* 10^{-12} m
8 0
3 years ago
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