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nlexa [21]
3 years ago
13

Resuelve:

Physics
1 answer:
Arlecino [84]3 years ago
3 0

The work done is 1764 J

Explanation:

The work done in lifting an object is equal to the gain in gravitational potential energy of the object:

W=mg \Delta h

where

m is the mass of the object

g is the acceleration of gravity

\Delta h is the change in height of the object

For the object in this problem, we have

m = 100 kg

g=9.8 m/s^2

\Delta h = 3 m -120 cm = 3 m- 1.20 m = 1.80 m

Therefore, the work done is

W=(100)(9.8)(1.80)=1764 J

Learn more about work and potential energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.
fenix001 [56]

Question

What is the length of the pipe?

Answer:

(a) 0.52m

(b) f2=640 Hz and f3=960 Hz

(c) 352.9 Hz

Explanation:

For an open pipe,  the velocity is given by

v=\frac {2Lf}{n}

Making L the subject then

L=\frac {nV}{2f}

Where f is the frequency,  L is the length,  n is harmonic number,  v is velocity

Substituting 1 for n,  320 Hz for f and 331 m/s for v then

L=\frac {1*331}{2*320}=0.5171875\approx 0.52m

(b)

The next two harmonics is given by

f2=2fi

f3=3fi

f2=3*320=640 Hz

f3=3*320=960 Hz

Alternatively, f2=2\times \frac {v}{2L} and f3=3\times \frac {v}{2L}

f2=2\times \frac {331}{2*0.52}=636.5 Hz\\f3=3\times \frac {331}{2*0.52}=954.8 Hz

(c)

When v=367 m/s then

f1= \frac {v}{2L}\\f1= \frac {367}{2*0.52}=352.9 Hz

5 0
3 years ago
The table describes the properties of four compounds.
irga5000 [103]

Answer:

compounds C and D

Explanation:

I believe this is correct

8 0
3 years ago
Read 2 more answers
Loops in a motor rotate because?​
ch4aika [34]

Answer:

Motors are the most common application of magnetic force on current-carrying wires. Motors have loops of wire in a magnetic field. When current is passed through the loops, the magnetic field exerts torque on the loops, which rotates a shaft. Electrical energy is converted to mechanical work in the process

Explanation:

hope that helps!

5 0
3 years ago
How much work is done when a hoist lifts a 210-kg rock to a height of 3 m? (Use 9.8 m/s2 for the acceleration due to gravity.)
Aleksandr [31]

Work done to lift the rock is 6174 Joule.

To find the answer, we need to know about the work done.

<h3>What's the work done?</h3>

Mathematically, work done = force × distance

<h3>What's the gravitational force acts on the stone here?</h3>

The gravitational force on the stone = mg

= 210× 9.8= 2058N

<h3>What's the work done to lift the stone?</h3>

Work done= 2058× 3

= 6174 Joule

Thus, we can conclude that the work done to lift the stone is 6174 Joule.

Learn more about the work done here:

brainly.com/question/25573309

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4 0
2 years ago
What requirement must a force acting on a object satisfy in order for the object to undergo simple harmonic motion?
viktelen [127]

Answer:

Simple harmonic motion is the movement of a body or an object to and from an equilibrium position. In a simple harmonic motion, the maximum displacement (also called the amplitude) on one side of the equilibrium position is equal to the maximum displacement.

The force acting on an object must satisfy Hooke's law for the object to undergo simple harmonic motion. The law states that the force must be directed always towards the equilibrium position and also directly proportional to the distance from this position.

6 0
3 years ago
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