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kkurt [141]
3 years ago
10

4. Naming Molecules a) Describe how ionic bonds are formed at the atomic level.

Chemistry
1 answer:
RoseWind [281]3 years ago
8 0

Explanation:

Ionic bonds involve a cation and an anion. The bond is formed when an atom, typically a metal, loses an electron or electrons, and becomes a positive ion, or cation. Another atom, typically a non-metal, is able to acquire the electron(s) to become a negative ion, or anion.

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How many moles of gas would occupy a 25.0 liter when the temp is 22.0 degrees celsius and the pressure is 646 torr
Luda [366]

Answer:

0.877 mol  

Step-by-step explanation:

We can use the<em> Ideal Gas Law </em>to solve this problem.

pV = nRT     Divide both sides by RT

 n = (pV)/(RT)

Data:

p = 646 torr

V = 25.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 22.0 °C

Calculations:

(a) <em>Convert the pressure to atmospheres </em>

p = 646 torr × (1 atm/760 torr) = 0.8500 atm

(b) <em>Convert the temperature to kelvins </em>

T = (22.0 + 273.15) K = 295.15 K

(c) <em>Calculate the number of moles </em>

n = (0.8500 × 25.0)/(0.082 06 × 295.15)

  = 0.877 mol

3 0
3 years ago
4.0 L sample of methane gas is collected at 30.0c,<br> what is the volume of the sample at -8c?
Vedmedyk [2.9K]
This particular law is a gas law, called Charle's Law. The formula is:

V1    V2
---- = ----
T1     T2

So we know our original volume is 4.0L, so we would plug that into our V1. We know T1 is the 30 degrees, since it relates to our original volume. However, we need to convert it to kelvin. We do this simply by adding 273 degrees to the 30 degrees, since 273 is the constant for kelvin.

We do not know our second volume, however we know out T2. It is -8 degrees, and don't forget to convert it to Kelvin. 

So, when we plug all of these numbers into the equation, we are left with V2 to find. To do this we cross multiply (V1 x T2) and then divide by T1. That leaves us with the number for V2. Don't forget to round to the least # of sig figs! And you can divide V1 by T1, and then divide V2 by T2, to ensure your answers are the same, since they are directly porportional and need to be equal to each other. 

Hope I could help!
8 0
4 years ago
vaporized at 100°C and 1 atmosphere pressure. Assuming ideal gas 1 g mole of water is behavior calculate the work done and compa
Vesna [10]

Answer:

q = 40.57 kJ; w = -3.10 kJ; strong H-bonds must be broken.

Explanation:

1. Heat absorbed

q = nΔH = 1 mol × (40.57 kJ/1 mol) = 40.57 kJ

2. Change in volume

V(water) = 0.018 L

pV = nRT

1 atm × V = 1 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 373.15 K

V = 30.62 L

ΔV = V(steam) - V(water) = 30.62 L - 0.018 L = 30.60 L

3. Work done

w = -pΔV = - 1 atm × 30.60 L = -30.60 L·atm

w = -30.60 L·atm × (101.325 J/1 L·atm) = -3100 J = -3.10 kJ

4. Why the difference?

Every gas does 3.10 kJ of work when it expands at 100 °C and 1 atm.

The difference is in the heat of vaporization. Water molecules are strongly hydrogen bonded to each other, so it takes a large amount of energy to convert water from the liquid phase to the vapour phase.

7 0
4 years ago
Name each compound. Do not capitalize element names. An example can be seen
miskamm [114]

Answer:

a. H2O: dihydrogen monoxide

b. PCl5: Phosphorus pentachloride

c. SiF4: Silicon tetrafluoride

d. N20: dinitrogen oxide

3 0
3 years ago
A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi
Dvinal [7]

Answer: D) More moles of ions are present in a given volume of 0.10 M Na_2SO_4 than in the same volume of 0.10 M NaCl.

Explanation:

A electrolyte is a solution that dissociates completely when dissolved in water. The ions act as good conductors of electric current in the solution.

More is the number of ions , more will be the conductance and hence the solution will be a better conductor of electricity.

0.10 M aqueous solution of Na_2SO_4 is a better conductor of electricity as it dissociates to give three ions whereas 0.10 M aqueous solution of NaCl dissociates to give two ions only.

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

NaCl\rightarrow Na^++Cl^{-}

Thus 0.10 M aqueous solution of sodium sulfate, Na_2SO_4 , is a better conductor of electricity as more moles of ions are present in a given volume of 0.10 M Na_2SO_4 than in the same volume of 0.10 M NaCl

3 0
4 years ago
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