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Stolb23 [73]
4 years ago
14

A science-fiction tale describes an artificial "planet" in the form of a band completely encircling a sun. The inhabitants live

on the inside surface (where it is always noon). Imagine that this sun is exactly like our own, that the distance to the band is the same as the Earth-Sun distance (to make the climate temperate), and that the ring rotates quickly enough to produce an apparent gravity of g as on Earth. What will be the period of revolution, this planet's year, in Earth days?
Physics
1 answer:
pickupchik [31]4 years ago
4 0

Answer:

Refer below for the explanation.

Explanation:

With the Sun sparkling on that band without pause and expecting that an environment like Earth's could be kept up (which it can't), that temperature would soar and before long become dreadful.

So the main issue here is to discover the period T that yields

=2*pie*squareroot(93E6*5280/32.2)

= 775908.2472 = 77.6E4 seconds or 1.283 weeks or around 9 days.

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Answer:

The speed will be "3.4×10⁴ m/s²".

Explanation:

The given values are:

Angular speed,

w = 7200 rpm

i.e.,

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  = 753.6 \ rad/s

Speed from the center,

r = 6.0 cm

As we know,

⇒  Linear speed, v=wr

On putting the estimated values, we get

                               =753.6\times 0.06

                               =45.216 \ m

Now,

Acceleration on disk will be:

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       =34074 \ m/s^2

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3 0
3 years ago
Suppose a 1 Gbps point-to-point link is being set up between the Earth and a new lunar colony. The distance from the moon to Ear
vagabundo [1.1K]

Answer:

The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>

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As, v=d/t

t=d/v

t=\frac{3.85*10^{8} }{3*10^{8}}

t=1.28s

RTT = Double of single way time taken = 2x1.28

<em><u>RTT=2.56s</u></em>

7 0
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Explanation:

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Answer:

for X, it's 50 times cos 35.

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Answer:

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