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krek1111 [17]
3 years ago
10

In what other planets did differentiation occur?

Chemistry
1 answer:
RSB [31]3 years ago
3 0

Venus, Mercury and Mars are the differentiated planets. Planetary differentiation can be defined as the process by which the separation of different types of constituents takes place.

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What is the final temperature of a 34.2 g of water initially at 282 K that has been heated with 2.71 kJ of energy?
lana66690 [7]

Answer: The final temperature of copper is  

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

                                       …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

                                   …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

So the value of Q can b calculated as follows:

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is .

Substitute these values in equation (2).

The temperature change  can be calculated as follows:

                         …… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

                      …… (4)

The value of  is .

The value of  is  

Substitute these values in equation (4).

So the final temperature of copper is .

7 0
2 years ago
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