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3 years ago

6

Granite lasts a long time when it is used for building in areas where

1 answer:

Kipish [7]3 years ago

3 0

B is the correct answer

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Which category of elements coposes groups 1-12 on the periodic table?

Dimas [21]

I'm pretty sure its metals.

5 0

4 years ago

Which of the following sentences represents a physical change? sugar dissolves in coffee iron rusts gasoline burns in an engine

MAXImum [283]

<u><em>Answer:</em></u>

Physical changes example is sugar dissolves in coffee
Chemical changes examples are iron rusts, gasoline burns in an engine and a candle burns.

Explanation.

Physical changes depend on only physical state, not on composition, which can be separated by physical means while chemical changes depend on composition and only separated by chemical ways.
As in case of iron rusting, gasoline and candle burn are cases chemical changes bcz they convert into another substance whose composition is different from other as compare to sugar which has same composition in coffee ,only state is changed from solid to liquid.

6 0

3 years ago

Read 2 more answers

Do females take longer to eliminate alcohol than male, even though they might be the same weight ?

natita [175]

The answer to this question is false

6 0

3 years ago

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If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

moles of $NaOH$ = $\frac{57.4\times 1000g}{40g/mol}=1435moles$

moles of $HF$ = $\frac{57.4\times 1000g}{20g/mol}=2870moles$

As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

Mass of cryolite $(Na_3AlF_6)$ = $moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg$

Thus 69.72 kg of cryolite will be produced.

8 0

3 years ago

How do you calculate metal density?

nekit [7.7K]

Answer:

You can divide the mass by the volume to calculate the density of the metal

Explanation:

7 0

3 years ago