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IrinaK [193]
3 years ago
11

The mechanical advantage of a wheel and axle is the radius of the wheel divided by the radius of the axle. On wheel and axle A,

the wheel and axle are very close in size. On wheel and axle B, the radius of the wheel is much greater than the radius of the axle.
Which wheel and axle has the greater mechanical advantage?
Physics
2 answers:
Montano1993 [528]3 years ago
7 0

Answer:

Wheel and axle B

Explanation:

It is given that the mechanical advantage of a wheel and axle is the radius of the wheel divided by the radius of the axle.

Mathematically, it can be written as :

MA=\dfrac{r_w}{r_a}.................(1)

On wheel and axle A, the wheel and axle are very close in size while on wheel and axle B, the radius of the wheel is much greater than the radius of the axle.

From equation (1) it is clear that the mechanical advantage is directly proportional to the radius of wheel.

So, the mechanical advantage of wheel and axle B is greater.

sergij07 [2.7K]3 years ago
4 0
Wheal and axle B has greater mechanical advantage
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A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

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Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

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3 years ago
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It seems to support that forced applied on an object when the object is in contact with other.

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3 years ago
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Vf1 = ?

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Replacing:

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1 year ago
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