The mechanical advantage of a wheel and axle is the radius of the wheel divided by the radius of the axle. On wheel and axle A,
2 answers:
Answer:
Wheel and axle B
Explanation:
It is given that the mechanical advantage of a wheel and axle is the radius of the wheel divided by the radius of the axle.
Mathematically, it can be written as :
.................(1)
On wheel and axle A, the wheel and axle are very close in size while on wheel and axle B, the radius of the wheel is much greater than the radius of the axle.
From equation (1) it is clear that the mechanical advantage is directly proportional to the radius of wheel.
So, the mechanical advantage of wheel and axle B is greater.
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Answer:
The maximum radius the asteroid can have for her to be able to leave it entirely simply by jumping straight up is approximately 1782.45 meters
Explanation:
Whereby the height the astronaut can jump on Earth = 0.500 m, we have the following kinematic equation;
v² = u² - 2·g·h
Where;
v = The final velocity
u = The initial velocity
g = The acceleration due to gravity ≈ 9.8 m/s²
h = The height she jumps
At the maximum height, = 0.500 m, she jumps, v = 0, therefore, we have;
0² = u² - 2·g·
u² = 2 × 9.8 × 0.5 = 9.8
u = √9.8 ≈ 3.13
u = 3.13 m/s
Her initial jumping velocity ≈ 3.13 m/s
Escape velocity,
Where;
M = The mass of the asteroid
G = The Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
r = The radius of the asteroid
The average density of the Earth = 5515 kg/m³
The mass of the asteroid, M = Density × Volume = 5515 kg/m³× 4/3 × π × r³
The escape velocity, she has, ≈ 3.13 m/s is therefore;
Therefore, the maximum radius of the asteroid can have for her jumping velocity to be equal to the escape velocity for her to be able to leave it entirely simply by jumping straight up = r ≈ 1782.45 meters.