Answer:
0.325 N
Explanation:
From the question,
T = 4π²rm/t²............................ Equation 1
Where T = Tension, r = radius or length of the string, m = mass of the string, t = time.
Given: r = 2.4 m, m = 15 g = 0.015 kg, t = 2.09 s.
Constant: π = 3.14
Substitute these values into equation 1
T = 4(3.14²)(2.4)(0.015)/2.09²
T = 1.4198/4.3681
T = 0.325 N
Answer:
0.025 m
Explanation:
From the question,
Applying Hook's law
F = ke................... Equation 1
Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.
make e the subject of the equation
e = F/k....................... Equation 2
Given: F = 10 N, e = 395 N/m
Substitute these values into equation 2
e = 10/395
e = 0.025 m
Explanation:it is beause they are sharper and also have less surface area and therefore more pressure
