Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
just use this formula and plug in all your values since im suffering trying to type all of this out on a keyboard but use this formula D= if you insert ur points in here you will get distance between each point . hope this helped i think this formula may not be what the question is asking but its the formula to find distance between points so
Answer:
Third answer shown
Step-by-step explanation:
Since each equation has a right side equal to the same thing, y, those right sides must be equal to each other.
x + 3 = -2x + 6
Add 2x to both sides. 2x 2x
3x + 3 = 0 + 6
3x + 3 = 6
Subtract 3 on both sides. -3 -3
3x = 3
Divide both sides by 3. x = 1
Now, let's see what y must be if x equals 1.
Line M: y = x + 3 --> y = 1 + 3 --> y = 4
Line N: y = -2x +6 --> y = -2(1) +6 --> y = -2 + 6 --> y = 4, confirmed
So the ordered pair (x, y) that satisfies <u><em>both </em></u>equations is (1, 4)
*** This means that if you graphed both lines on an xy-coordinate plane, the point (1,4) would be the point where the two lines intersect.
That is the third answer shown.
To get rid of the parenthesis, we use the Distributive Property.
8x + 4x - 4
Now, we add the like terms.
12x - 4
The answer is B, 12x - 4. You were really close!
Hope this helps!