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Darina [25.2K]
3 years ago
8

. Consider this word problem about baking brownies: You are baking brownies for your class. You put white frosting on 1 you put

small red hearts on 1 3 of the brownies and 4 of the brownies. How many brownies have both white frosting and small red hearts on them?
Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

The fraction of brownies with both white frosting and small red hearts is not given. And also the total number of brownies made is not given too.

Therefore, the number of brownies that have both white frosting and small red hearts on them cannot be determined

Step-by-step explanation:

Given;

1. You put 1 white frosting per 3 of the brownies

2. You put 1 small red hearts per 4 of the brownies

Fraction of brownies with;

White frosting = 1/3

Small red hearts = 1/4

The fraction of brownies with both white frosting and small red hearts is not given. And also the total number of brownies made is not given too.

Therefore, the number of brownies that have both white frosting and small red hearts on them cannot be determined

For example:

Assuming that;

The fraction of brownies with both white frosting and small red hearts = 1/12

The total number of brownies baked = 36

The number of brownies with both white frosting and small red hearts = 1/12 × 36 = 3 brownies.

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Find the x- and y- intercepts of parabola y=5x^2-16x+10
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Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

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The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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2 years ago
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kondor19780726 [428]

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

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The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

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To get the function we use one of the point (2,0) and a general point (x,y).

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1/2 = y/(x - 2)

(x - 2) = 2y

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3 years ago
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padilas [110]

Hello :)

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Write the equation of the line given the slope and a point through the line passes
Anuta_ua [19.1K]

Answer:

1.) Y = 5/3 X + 4

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Step-by-step explanation:

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