Answer:
τ = 0.00203 seconds
Explanation:
The time constant τ in a R-L circuit is given by
τ = L/R
First we have to find out the equivalent resistance of the circuit.
Since there is a parallel combination of 19 Ω and 6.0 Ω resistor
Req = 19*6/19+6
Req = 4.56 Ω
Now we can find out the time constant
τ = L/R
τ = 0.0093/4.56
τ = 0.00203 seconds
Therefore, the time constant of this circuit is 0.00203 seconds.
Answer:
NO
Explanation:
Acceleration is change in velocityΔv in respect to timeΔt
so if the velocity of the car is greater than the truck it does not mean that the car acceleration is greater than the truck.
Sometimes with constant velocity it means no accelaration ,but the truck may have accelaration
so, higher velocity of the car does not mean higher acceleration
Answer:
a) Posición y velocidad después de los 6s
i) Posición = -26.58m
ii) velocidad = -33.86m/s
b) Tiempo para alcanzar la altura máxima
= 2.55s
c) Alcance horizontal
= 220.7m
Explanation:
a) Posición y velocidad después de los 6s
i) Posición
y = (usinθ)t – 1/2 gt²
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
y = (50 × sin 30)6 - 1/2 × 9.81 × 6²
y = 150 - 176.58
y = -26.58m
ii) velocidad
v = u sinθ–gt
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
v = 50 × sin 30 - 9.81 × 6
v = 25 - 58.86
v = -33.86m/s
b) Tiempo para alcanzar la altura máxima
usinθ /g
u = 50m/s
θ = 30°
g = 9.81m/s²
= 50 × sin 30/ 9.81
= 25/9.81
= 2.5484199796s
≈ 2.55s
c) Alcance horizontal
R = u²sin2θ/g
u = 50m/s
θ = 30°
g = 9.81m/s²
R = 50² ×( sin 2 ×30°) /9.81
R = 220.69964419m
≈ 220.7m
The magnitude of the electrostatic force between the two charges is 
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:

where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have:


r = 20.0 cm = 0.20 m
Therefore, the force between the charges is

where the negative sign means that the force is attractive, since the two charges have opposite sign.
Learn more about electrostatic force here:
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