?
1 answer:
You might be interested in
Answer:
The speed is
Explanation:
Electric field magnitude (E) and electric force magnitude (F) are related by the equation
with q the charge of the proton (). Because between parallel plates electric field is almost constant, electric force is constant too:
because electric force is constant, then by Newton's second law acceleration (a) is constant too, it is:
with m the mass of the proton ():
Now with this constant acceleration we can use the kinematic equation
with v the final speed, the initial velocity that is zero (because proton starts at rest) and d is the distance between the plates, so:
The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.