Answer:
We are asked to solve for the lateral area of the cylinder and the formula is shown below:
Lateral area = 2*pi*r*h
We are also given with the area of the base such as:
Area of the base = 36pi square units
Area of the base = pi*r²
Solving for radius:
36pi = pi*r²
r=6 inches
Solving for the lateral area when height is 2 units:
Lateral area = 2*pi*6*2
Lateral area = 24pi inches²
The answer is the letter "B" 24 square units
Step-by-step explanation:
Answer:
The answer is 405
Step-by-step explanation:
FIrst you would do 27 times 30 which is 810 then you would divided by 2 which in turn gives you 405
Hope this helped!
Answer: about 34.6
Step-by-step explanation: 11 is the radius, but you need the diameter which is 22. multiply 22 by pi and divide that number by 2 since it is half a circle.
When you have an irregular figure, you can divide it so that it becomes multiple normal figures. You already did this in the picture, now you just have to find the area of each shape and then add them all together.
From bottom to top:
A=1/2 (b1+b2)h
A= 1/2 (4+2.24)(2)
A= 6.24
(you have two of these on either side)
A=bh
A=6(4)
A=24
A=1/2 bh
A= 1/2 (4)(4)
A=8
(NOTE: there is an error in your drawing. The height of the triangle cant be determined because the 10 value spans over the entire figure when the wings of the rocket are 4 units long and then the body is 6 units long, making it equal 10 already. I'm assuming that the 10 is supposed to go from the bottom of the rectangle to the top of the triangle)
Total figure= 6.24 + 6.24 + 24 + 8
total figure = 44.48
