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2 years ago

Why don't satellites in orbit fall to the ground? Why they don't fly off into space?

2 answers:

6 0

-- The satellite IS falling, but it never reaches the ground because
it's also moving "sideways" ... in the direction of the orbit ... and
because the Earth is shaped like a sphere.

The satellite is moving sideways fast enough so that by the time
it falls 1 foot, the Earth's surface has curved down away from it
1 foot, so it's still the same distance from the Earth's surface.

-- A satellite doesn't fly off into space for the same reason that
a yo-yo doing "around the world" on the end of a string doesn't
fly off ... It's being held onto the circle by the tension in the string,
a force that keeps pulling it toward the center of the circle.

There's a force on the satellite too, that keeps pulling it toward
the center of the Earth. It's the gravitational force between the
Earth and the satellite.

The satellite doesn't fly off into space for the same reason that
YOU don't do that either.

Molodets [167]2 years ago

4 0

They are held in earths gravity.

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Answer:

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

$L_i = L_f$

now we have

$L_i = (\frac{1}{2}MR^2)\omega_o$

also we have

$L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now from above equation we have

$(\frac{1}{2}MR^2)\omega_o = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now we have

$\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}$

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

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3 years ago

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3 years ago

How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it duri

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Answer:

Water gains energy during evaporation and releases it during condensation in the atmosphere

Explanation:

In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.

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In condensation, the molecules of gaseous water looses energy and becomes liquid.

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If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the

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The change in the internal energy of the system is 110 kJ.

<h3>What is internal energy?</h3>

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

ΔU = Q-W.................... Equation 1

Where:

ΔU = Change in internal energy
Q = Heat absorbed from the surroundings
W = work done by the system

From the question,

Given:

Q = 115 kJ

W = 45. 0 kJ

Substitute these values into equation 1

ΔU = 155-45

ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

Learn more about change in internal energy here: brainly.com/question/4654659

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2 years ago