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4 years ago

Describe two ways that setting fishing limits can help protect fish species

1 answer:

5 0

Setting fishing limits on certain fish species is essential because if overfishing is allowed, the fish won't be able to reproduce fast enough to outpace their removal. Fishing limits also put more emphases on catching other species, which protects the original species from predators.

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The pH of coffee is _______ times greater than the pH of pure water.

DENIUS [597]

Answer:

zero times greater

Explanation:

Coffee's pH level is 5

Pure water's pH level is 7

3 0

3 years ago

A reaction mixture in a 3.67 L flask at a certain temperature initially contains 0.763 g H2 and 96.9 g I2, At equilibrium, the f

Alexxandr [17]

Answer:

13 530 482

Explanation:

H2 + I2 ------> 2HI

start (mol) 0.3785 0.3818 0

change (mol) -0.3534 -0.3534 +0.7067

equilibrium (mol) 0.0251 0.0284 0.7067

concentra (mol/L) 0.0068 0.0077 0.1926

$K_{c} = \frac{0.1926^{2}}{0.0068^{2}*0.0077^{2} } = 13530482$

7 0

3 years ago

The temperature of 1 m^3 of water is decreased by 10°C. If this thermal energy is used to lift the water vertically against grav

Rama09 [41]

Answer:

h = 4271.43 m

Explanation:

given,

Volume of the water = 1 m³

temperature decrease by = 10°C

heat removed from water

Q = m c ΔT

Q = ρ V c ΔT

= 1000 × 1 × 4186 × 10

= 4.186 × 10⁷ J

energy is used to do work to move the water against its weight

Q = force × displacement

4.186 × 10⁷ J = m g × h

4.186 × 10⁷ J = 1000 × 1 × 9.8 × h

h = 4271.43 m

hence, the change in height of is equal to h = 4271.43 m

8 0

4 years ago

HELP PLS WHAT IS Y COMPONENT

jeka94

Answer:

11.5

Explanation:

you do 12(sin 73.3) because its on the y you do sin

6 0

3 years ago

A boat heads directly across a river. Its speed relative to the water is 3 m/s. It takes it 539 seconds to cross, but it ends up

nikklg [1K]

Answer:

3.24 m/s

Explanation:

Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream

Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

$v_r = 662 / 539 = 1.23 m/s$

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:

$v = \sqrt{v_b^2 + v_r^2} = \sqrt{3^2 + 1.23^2} = \sqrt{9 + 1.5129} = \sqrt{10.5129} = 3.24$ m/s

5 0

4 years ago