By definition for an elastic shock, we have that if the second particle is at rest, then the final velocity of the first particle will be given by vf1 = ((m1-m2) * vi1) / (m1 + m2). Then, substituting the values: vf1 = ((0.1-0.3) * 10) / (0.1 + 0.4) = - 5m / s.
According to James-Lange theory of emotion, a stimulus first leads to bodily arousal, and this is followed by our interpretation of it as an emotion.
Answer:
30 m/s
Explanation:
Applying,
v = u+at................ Equation 1
Where v = final speed of the ball, u = initial speed of the ball, a = acceleration, t = time.
From the question,
Given: u = 0 m/s (stationary), a = 600 m/s², t = 0.05 s
Substitute these values into equation 5
v = 0+(600×0.05)
v = 30 m/s
Hence the speed at which the ball leaves the player's boot is 30 m/s
I disagree that folk dance forms can be outside their original meaningful form in this scenario.
<h3>What is Folk dance?</h3>
This is the type of dance which is unique to a particular set of people and helps celebrate their culture.
This dance is a ritualistic entertainment which is done in different type of gatherings such as ceremonies etc which is why it isn't outside their original meaningful form.
Read more about Folk dance here brainly.com/question/18269425
