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Viefleur [7K]
4 years ago
8

ListenA person weighing 6.0 × 102 newtons rides an elevator upward at an average speed of 3.0 meters per second for 5.0 seconds.

How much does this person’s gravitational potential energy increase as a result of this ride? a) 3.6 × 102 J b) 1.8 × 103 J c) 3.0 × 103 J d) 9.0 × 103 J.
Physics
1 answer:
pychu [463]4 years ago
4 0

Answer:

(d) 9 × 10^{3] J

Explanation:

from the question we are given the following:

weight of the man = 6.0 × 10 ^ {2} N

average speed (v) = 3 m/s

time (t) = 3 s

potential energy (U) = ?

We can calculate the increase in potential energy of the man by applying the formula below

increase in potential energy = P₂ - P₁

where

  • P₁ is the initial potential energy
  • P₂ is the final potential energy
  • Potential energy = mass x acceleration due to gravity x height

From physic we know that weight = mass x acceleration due to gravity

  • We should take note that the distance in this case is also our height, and we can get it from the formula distance = velocity x time
  • Distance = 3 x 5 = 15 meters
  • Initial potential energy P₁ is zero because the person was initially in motion and potential energy is the energy at rest.

therefore

potential energy = 6.0 × 10 ^ {2} × 15 = 9 × 10^{3] J

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Kobotan [32]

Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

v = u + at

v = 44 + (-4 x 10)

v = 44 - 40

v = 4 m/s

Therefore, the final velocity of the train is 4 m/s.

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zlopas [31]

Answer:

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Explanation:

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          r = 6 , 37 106 m

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Now let's calculate the charge on the planet with E = 222 N / c and radius

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           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

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3 years ago
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<h2>Answer: A</h2>

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A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?
kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

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Rearranging the equation, we can write

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S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s

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