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3 years ago

How long does it take for the earth to rotate

Physics

2 answers:

zheka24 [161]3 years ago

6 0

It takes 24 hours to make a full rotation around the sun

GenaCL600 [577]3 years ago

5 0

It takes 24 hours to rotate around in a circle and 365 days to orbit around the sound cuz it takes 1 year to rotate around the sun and because it takes 1 day to rotate around in a circle.

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Your mom is making lunch which forces are acting on your mom

mote1985 [20]

Idk I need to answer a question to ask more so thanks bye

3 0

3 years ago

Read 2 more answers

Parallax error occurs when the observer records data when he/she is at an angle to the event he/she is observing. Where do you t

kompoz [17]

Answer:Orient your line of sight directly above the measurement markings.

Explanation: parallax error is a type of systematic error that occurs when an observer views a measurement marking at a wrong angle. This causes a noticeable disparity in results obtained. Therefore the best way to prevent this error is to view and record the data from the correct angle. This can be obtained by:

-Place the measurement device on its edge so it is level with the object being measured.

-Seek out the finest possible edge of the measurement device, or use a device with finer edges.

In conclusion, ask other observers to also take the reading and get an average of their results. It can help cancel out parallax error results.

4 0

4 years ago

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.2589 N when separated by

Harlamova29_29 [7]

Answer:

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

Explanation:

Let the initial charge on the two spheres are

$q_1, -q_2$

now we know that the force between them is given as

$F = \frac{kq_1q_2}{r^2}$

$0.2589 = \frac{kq_1q_2}{0.5^2}$

$q_1q_2 = 7.19 \times 10^{-12}$

now when two spheres are connected then final charge on them is given as

$q = \frac{q_1 - q_2}{2}$

now the force between them is given as

$0.3456 = \frac{k(q_1 - q_2)^2}{4(0.5)^2}$

now we have

$q_1 - q_2 = 6.19 \times 10^{-6}$

So by solving above two equations we have

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

3 0

3 years ago

A rocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/

klemol [59]

Answer:

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

$d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m$

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

$\Delta Y = Vo*sin(30)*t - \frac{g*t^2}{2}$