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3 years ago

Why it is not easy to whril a hammer by a longer chain?

Physics

1 answer:

-Dominant- [34]3 years ago

6 0

<span>because with a longer chain you are giving the hammer momentum so it will take more strength to move</span>

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Can someone help me?!!

Fantom [35]

<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

$F_y=Force*Sin(29\°)$

We are given that the force is equal to 30.0 N, so, calculating we have:

$F_y=Force*Sin(29\°)$

$F_y=30N*Sin(29\°)=14.5N$

Also, we can calculate the horizontal component of the force using the following formula:

$F_x=Force*Cos(29\°)$

$F_x=30N*Cos(29\°)=26.24N$

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

5 0

3 years ago

Which parts of the spectrum show the presence of elements in the stars atmosphere

Yuliya22 [10]

the one right behing 600 and the one in between 600 and 700

"please give me brainliest"

3 0

3 years ago

Read 2 more answers

Two converging lenses, one with f = 4.0 cm and the other with f = 37 cm , are made into a telescope. What is the length of this

d1i1m1o1n [39]

Answer:

The length and the magnification of this telescope are 41 cm and 0.108.

Explanation:

Given that,

Focal length of first lens f= 4.0 cm

Focal length of other lens f'= 37 cm

We need to calculate the length of the telescope

Using formula of length

$L=f+f'$

Put the value into the formula

$L=4+37=41 cm$

We need to calculate the magnification of the telescope

Using formula of the magnification

$m=\dfrac{f}{f'}$

Put the value into the formula

$m=\dfrac{4}{37}$

$m=0.108$

Hence, The length and the magnification of this telescope are 41 cm and 0.108.

8 0

3 years ago

A marble slides without friction in a vertical loop around the inside of a smooth, 28.6 cm diameter horizontal pipe. The marble'

Leviafan [203]

Answer:3.49 m/s

Explanation:

Given

Speed of marble at Bottom $v=4.22 m/s$

Diameter of loop $d=28.6 cm$

As Energy is conserved therefore Energy at top is equal to energy at bottom

$E_T=E_B$

$\frac{mv^2}{2}+mgh=\frac{mv_0^2}{2}$ ,where $v_0$ is the velocity at bottom

$\frac{v^2}{2}+gh=\frac{v_0^2}{2}$

$v_0^2=v^2+2gh$

$v^2=v_0^2-2gh$

$v=\sqrt{v_0^2-2gh}$

$v=\sqrt{4.22^2-2\times 9.8\times 0.286}$

$v=\sqrt{17.8084-5.6056}$

$v=3.49 m/s$

7 0

3 years ago

Unit 12 Exam

lapo4ka [179]

Answer:

You increase the acceleration of the car.

6 0

3 years ago