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3 years ago

15

Children are told to avoid standing too close to a rapidly moving train because they might get sucked under it. Is this possible

? Explain.

1 answer:

storchak [24]3 years ago

4 0

Answer:

no its not like the undertow in the ocean

Explanation:

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How does cancer change the normal life cycle of a cell ?

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In normal cells, the cell cycle is controlled by a complex series of signaling pathways by which a cell grows, replicates its DNA and divides.

In cancer, as a result of genetic mutations, this regulatory process malfunctions, resulting in uncontrolled cell proliferation.

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3 years ago

Which of the following medicinals are utilized to help reduce pain?

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3 years ago

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Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 secon

Musya8 [376]

Answer:

140 watt

Explanation:

We are given that

Force applied by student ,F=28 N

Weight pulled by students=70 N

Displacement,s=15 m

Time=3 s

We have to find the power developed by the student.

Work done=w= $F\times s$

Work done by the student= $28\times 15=420 J$

Power= $\frac{work\;done}{time}$

Using the formula

Power= $\frac{420}{3}=140watt$

Hence, the power developed by the students=140 watt

8 0

3 years ago

A car traveling in a straight line has a velocity of 5.0 m/s. After an acceleration of 0.75 m/s/s, the cars velocity is 8.0. In

Bogdan [553]

Vs - velocity on beginning
ve - velocity on ending. You've got:
$v_s = 5 \frac{m}{s} \\ v_e=8 \frac{m}{s} \\ \hbox{Then:} \\ \Delta v=v_e - v_s = 8 \frac{m}{s} - 5\frac{m}{s}=3 \frac{m}{s} \\ a=0,75 \frac{m}{s^2} \\ \hbox{And from formula:} \\ a=\frac{\Delta v}{\Delta t} \qquad \Rightarrow \qquad \Delta t= \frac{\Delta v}{a} \\ \hbox{Substitute:} \\ \Delta t=\frac{3\frac{m}{s}}{0,75 \frac{m}{s^2}}= \frac{3}{\frac{3}{4}} s= 3 \cdot \frac{4}{3} s= 4 s$
So he needed 4 second.

3 0

3 years ago

A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec

Wewaii [24]

Answer:

Velocity = 0.4762 m/s

Explanation:

Given the details for the simple harmonic motion from the question as:

Angular frequency, ω = 12 rad/s

Amplitude, A = 0.060 m

Displacement, y = 0.045 m

The initial Energy = U = (1/2) kA²

where A is the amplitude and k is the spring constant.

The final energy is potential and kinetic energy

K + U = (1/2) mv² + (1/2) kx²

where x is the displacement

m is the mass of the object

v is the speed of the object

Since energy is conservative. So, the final and initial energies are equal as:

(1/2) k A² = (1/2) m v² + (1/2) kx²

Using, ω² = k/m, we get:

Velocity:

$v=\omega\times \sqrt{[ A^2 - y^2 ]}$

$v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}$

<u>Velocity = 0.4762 m/s</u>

4 0

3 years ago