What are some examples of lipids?

A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s

s344n2d4d5 [400]

We first calculate the heat released:
Specific heat = 3.21 kJ/kgK
Heat released = heat absorbed by calorimeter
Heat absorbed = mcΔT
= 1.9 x 3.21 x 4.542
= 27.7 kJ

Now, we calculate the moles of hexane present:
Moles = mass / Mr
moles = 0.58 / (12 x 6 + 14)
= 0.0067

Heat of combustion = 27.7 / 0.0067 kJ/mol

ΔH(combustion) = 4,134.3 kJ / mol

8 0

3 years ago

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How many hydrogen bonds can CH3NH2 make to water?

ikadub [295]

CH3NH2 can only have as many hydrogen bonds as hydrogen bonding sites in the molecule. CH3NH2 has two N−H bonds and a lone pair of electrons on the nitrogen atom. Therefore, CH3NH2 can form three hydrogen bonds with water.

4 0

3 years ago

The process that is the opposite of sublimation is called deposition. Use the example of frost formation to infer why this proce

Vedmedyk [2.9K]

Answer:

See explanation

Explanation:

Sublimation refers to the movement of molecules directly from solid into the vapor or gas phase while deposition refers to the movement of molecules directly from the gas phase into the solid phase. The two are opposite to each other.

Frost is formed in a situation where a substance cools to a temperature that is lower than its dew point. In this situation, the vapour is directly deposited on a surface to form a frost without passing through a liquid phase. Hence the name, deposition.

7 0

3 years ago

Why do elements within a group have similar chemical properties?

creativ13 [48]

Because they have the same number of valence electrons.

4 0

3 years ago

Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the numbe

yuradex [85]

Answer:

The ratio of pressure in bottle B to that of bottle A is 1 : 4

Explanation:

We'll be by calculating the pressure in both bottles. This is illustrated below below:

For A:

Temperature (T) = T

Volume (V) = V

Number of mole (n) = n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

PV = n x 0.0821 x T

Divide both side by V

P = nT0.0821/V

Therefore, the pressure, in bottle A is

PA = nT0.0821/V

For B:

Temperature (T) = the same as that of A = T

Volume (V) = twice that of A = 2V

Number of mole (n) = half that of A = ½n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

P x 2V = ½n x 0.0821 x T

Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

PB = nT0.0821/4V

Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

Pressure in bottle A (PA) = nT0.0821/V

Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.

3 0

3 years ago