Answer:
3.66 moles of Zinc Oxide are consumed
Explanation:
Based on the reaction:
C + 2ZnO → 2Zn + CO₂
<em>Where 1 mole of Carbon reacts with 2 moles of Zin Oxide to produce 2 moles of Zinc and 1 mole of Carbon Dioxide.</em>
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To solve this question, we must convert the moles of carbon added to the moles of Zinc Oxide that react using the chemical equation (1mol C = 2mol ZnO):
1.83 moles C * (2mol ZnO / 1mol C) =
<h3>3.66 moles of Zinc Oxide are consumed</h3>
Answer:
Three
Explanation:
1. Draw a Lewis structure
- Put the least electronegative atom (C) in the centre
- Attach the O and two S atoms to the C.
- Add enough electrons to give each atom an octet.
2. Draw the resonance structures
You should get one of the structures below.
It has a double bond and two single bonds.
The resonance structures will have the double bond in each of the other two positions.
Metals are -shiny- because light reflects off the electrons.
Answer:
The mole fraction of codeine is 5.4%
Explanation:
Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)
Solute (Codeine)
Molar mass 299.36 g/m
Mass / Molar mass = Mole → 46.85 g /299.36 g/m = 0.156 moles
Solvent (Ethanol)
Molar mass 46.07 g/m
125.5 g / 46.07 g/m = 2.724 moles
Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054
Answer:
The answer to your question is 1.36 x 10²³ atoms
Explanation:
Data
number of atoms = ?
mass of the sample = 34.2 g
Molecule = Cl₂O₅
Process
1.- Calculate the molar mass of Cl₂O₅
Cl₂O₅ = (35.5 x 2) + (16 x 5) = 71 + 80 = 151 g
2.- Calculate the atoms of Cl₂O₅
151 g of Cl₂O₅ ---------------- 6 .023 x 10²³ atoms
34.2 g of Cl₂O₅ ------------ x
x = (34.2 x 6.023 x 10²³) / 151
x = 1.36 x 10²³ atoms
