Answer:
73 and 15
Step-by-step explanation:
I made two variables for this:
x = larger number
y = smaller number
Write an equation for "the sum of two number is 88" and you get:
x + y = 88
Write an equation for "four times the smaller number is subtracted from the larger number" and you get:
x - 4y = 13
I do not want an equation with both x and y in it, so I will rewrite the first one and use substitution in the second one:
x + y = 88 -- move the x to the other side
y = 88 - x
x - 4y = 13 -- substitute for y
x - 4(88 - x) = 13 -- multiply by 4
x - 352 + 4x = 13 -- move -352 to the other side, combine x's
5x = 365 -- divide by 5
x = 73
Now that I know x is 73, I go back to my first equation (x + y = 88) and I get:
73 + y = 88 -- subtract 73 from both sides
y = 88 - 73
y = 15
We get tne n-th term with: tn=1/3tn-1
We know that the first term is t1=81, so 81=1/3t*1-1
81=1/3t-1
82=1/3t
82*3t=1
3t=1/82
t=1/82*3=1/246
The second term is: 1/
2*(1/246)*2)-1
We get the third term by replacing n with 3 and so on...
Answer: only one gambeler will win
Step-by-step explanation:
