How many moles of aluminum are needed to react completely with 1.2 mol of feo

Chemistry

1 answer:

Lelu [443]3 years ago

3 0

Answer:

0.80 mol Al

Explanation:

1) Word reaction:

Aluminum + ferrous oxide → aluminum oxide + iron

This is a single replacement reaction, in which aluminum, a more acitve metal than iron, replaces the iron in the ferrous oxide to form aluminum oxide and iron.

2) Skeleton chemical equation:

Al + FeO → Al₂O₃ + Fe

3) Balanced chemical equation:

Add the coeffcients to comply with the law of conservation of mass:

2Al + 3FeO → Al₂O₃ + 3Fe

4) Mole ratio of Al and FeO:

2 mol Al : 3 mol FeO

5) Set a proportion with the unkown and solve:

x / 1.2 mol FeO = 2 mol Al / 3 mol FeO

x = 1.2 mol FeO × 2 mol Al / 3 mol FeO = 0.80 mol Al ← answer

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vladimir1956 [14]

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3 years ago

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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$