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HACTEHA [7]
3 years ago
15

How many moles of aluminum are needed to react completely with 1.2 mol of feo

Chemistry
1 answer:
Lelu [443]3 years ago
3 0

Answer:

  • <u><em>0.80 mol Al</em></u>

Explanation:

<u>1) Word reaction:</u>

  • Aluminum + ferrous oxide → aluminum oxide + iron

This is a single replacement reaction, in which aluminum, a more acitve metal than iron, replaces the iron in the ferrous oxide to form aluminum oxide and iron.

<u>2) Skeleton chemical equation:</u>

  • Al + FeO → Al₂O₃ + Fe

<u>3) Balanced chemical equation:</u>

Add the coeffcients to comply with the law of conservation of mass:

  • 2Al + 3FeO → Al₂O₃ + 3Fe

<u>4) Mole ratio of Al and FeO:</u>

  • 2 mol Al : 3 mol FeO

<u>5) Set a proportion with the unkown and solve:</u>

  • x / 1.2 mol FeO = 2 mol Al / 3 mol FeO

  • x = 1.2 mol FeO × 2 mol Al / 3 mol FeO =<u> </u><u>0.80 mol Al ← answer</u>
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Why are non-metals dull in appearance as solids?
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6 0
3 years ago
Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) =&gt; CH 3OH(l) Using the following information: C(graphite) +
Alika [10]

Answer:

\Delta H for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

C(graphite)+O_{2}(g)\rightarrow CO_{2}(g) \Delta H_{1}= -393.5 kJ

2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l) \Delta H_{2}= (2\times -285.8)kJ

CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)  \Delta H_{3}= 726.4 kJ

---------------------------------------------------------------------------------------------------

C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ

4 0
3 years ago
EIGHTY POINTS- WILL GET BRAINLIEST NEED ANSWER ASAP
il63 [147K]

ans A. 13 to 3

solution:

Total puppies for sale=6

Total puppies left = 2

hence total puppies sold= 6 - 2 = 4

cost of a puppy= $ 104

so cost of 2 puppies = 104 x 4

=416$

Now for kittens:

Total kittens for sale = 12

Total kittens left = 8

hence total kittens sold=12 - 8 =4

cost of a kitten = $24

so cost of 4 kittens= 24x 4=96$

Now ratio of sales of puppies to kittens = 208$/96$

= 13/3 or 13:3 or 13 to 3

I hope this explanation will help you to understand this problem

5 0
2 years ago
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