Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a <u>primary substrate</u> (1-bromo-3,3-dimethylbutane). Because the <u>leaving grou</u>p "Br" is bonded to a <u>primary carbon</u>. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an <u>ionic compound</u>, so, in solution, a cation and an anion would be produced. The anion
would be the <u>nucleophile</u>.
Due to the primary substrate, we will have an <u>Sn2 reaction</u>. So, the attack of the nucleophile and the removal of the leaving group will take place in <u>1 step</u>. Producing a <u>"transition state"</u> and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
I hope it helps!
The much hydrogen that is produced is 0.02 mol of H₂ (answer B)
Explanation
2K +2H₂O→ 2 KOH + H₂
Use the mole ratio to determine the moles of H₂
From equation above the K :H₂ is 2:1
Therefore the moles of H₂ = 0.04 x 1/2 = 0.02 mol of H₂
Answer: The layers of the rocks in one region of the parks are smooth and distinct, which are evidence of many, many years of deposition. The layers on the rocks are because of different deposition of sediments. Different sediments deposited over the rocks through wind, water and ice over the ages
Explanation: