Answer: Option B. 76.83L
Explanation:
1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.
If 1 mole of Radon = 22.4L
Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L
HCl :
hydrochloric acid
answer A
hope this helps!
Answer:
Explanation:
H2SO4 let S be x
2(1) + x + 4(-2) = 0
2 + x - 8 = 0
x - 6 = 0
x = 6
For H2S7O8 let S be x
2(1) + 7(x) + 8(-2) = 0
2 + 7x - 16 = 0
7x - 14 = 0
7x = 14
x = 14/7
x = 2
:- H2SO4 as the larger percentage
For this problem, we use the Beer Lambert's Law. Its usual equation is:
A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution
As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:
A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
