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Kay [80]
3 years ago
5

Differentiate between Halogens and insert gases​

Chemistry
1 answer:
jasenka [17]3 years ago
6 0

Answer:

An inert gas is one that does not undergo chemical reactions

Noble gases refers to the right most group of the periodic table composed of helium, neon, argon, krypton, xenon, and radon. As you might have seen as an example in class, some noble gases can form chemical compounds, such as XeF4.

or to say:

Halogens and noble gases are two different groups of elements that can be seen on the periodic table. Halogens are found in group 17 and include fluorine, chlorine, bromine, iodine and astatine. Noble gases make up group 18, and include helium, neon, argon, krypton, xenon and radon.

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How many hydrogen atoms are in 89.5 g of<br> C6H6 ?<br> Answer in units of atoms.
Elodia [21]

Solution :

Molar mass of C_6H_6 is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of C_6H_6 contains 6.022 \times 10^{23} molecules.

So, 89.5 gram of C_6H_6 contains :

n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}

Now, from the formula we can see that one molecule of C_6H_6 contains 2 hydrogen atom . So, number of hydrogen atom are :

h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms

Hence, this is the required solution.

8 0
3 years ago
How many significant figures are in 4.800x10-3?​
seraphim [82]
4 after solving =0.004800 where 4,800 is the significant number
5 0
2 years ago
Select all of the answers that apply.
shtirl [24]
The odysseyware answer is the same as his wood manure and food crops
5 0
4 years ago
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A 76.00-pound flask of mercury costs $151.50. The density of mercury is 13.534 g/cm3.
Agata [3.3K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Please see below solution:

1 lb Hg x (151.50/76 lb) = cost of 1 lb. 
<span>cost 1 lb x (1g/453.6 g) = cost of 1 g.</span>
8 0
3 years ago
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The total volume required to reach the endpoint of a titration required more than the 50 mL total volume of the buret. An initia
Margaret [11]

Answer:

The endpoint volume is 50.52 ±  0.14 mL

Explanation:

In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:

V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)

V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL

V = 50.52 ±  0.14 mL

It is necessary to consider the sum of the errors too.

7 0
4 years ago
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