The phosphate ion has a formula of PO₄⁻³
It is visible that there is one phosphorus atom and four oxygen atoms. Moreover, we know that both phosphorus and oxygen are non-metallic elements, so the bonding that must be present between them is covalent bonding.
Finally, the charge of an ion is distributed over the entire ion so that it is stabilized. Thus, the answer is:
<span>It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion</span>
Answer:
2Mg^+ +O2 right arrow 2MgO
Explanation:
Answer:
See explanation and images attached
Explanation:
We know that the cis isomer has more heat of hydrogenation since it is less stable than the trans isomer. Since the hydrogenation of both compounds yields the same product and the hydroboration/oxidation both give a primary alcohol, they are geometric isomers and Y is the trans isomer (Image 2).
For the compound C8H12, the compound in question must be 1,5- cyclooctadiene since two moles of the same aldehyde was obtained after ozonolysis and reaction with two equivalents of hydrogen gives cyclooctane (Image 1).
Answer:
54.75 mL
Explanation:
First calculate the number of moles of NaCl in the 150mL solution of NaCl
0.0365 moles should be present on 1000cm3 or 1dm3 of water.
1L = 1 dm3
1 mL = 1 / 1000 dm3
150 mL = 150/1000 dm3 = 0.15 dm3
If x moles are present in 0.15 dm3,
x/ 0.15 = 0.0365
We get x= 0.0365 × 0.15 mol
Now x amount of moles should be taken from the initial 0.100 M NaCl solution
So 0.1 moldm-3 = 0.0365× 0.15 mol / V
we get V = 0.05475 dm3
V= 0.05475 L
V= 54.75 mL
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.
Now, Molarity = </span>

=

<span> =
0.002995 mol/dm3Answer: Molarity of solution = </span>
0.002995 mol/dm3<span>
</span>