Answer:
x = -2
Step-by-step explanation:
For this problem, we must simply solve for x. To do this, we will need equation operations, and the use of the distributive property.
Let's work this line by line until we have the value for x:
3{-x + (2x + 1)} = x - 1
3*-x + 3*(2x + 1) = x - 1
-3x + 6x + 3 = x - 1
3x + 3 = x - 1
2x = -4
x = -2
Now we can check our answer for x by plugging back into the original equation and see if the left hand side is equal to the right hand side:
3{-x + (2x + 1)} = x - 1
3{-(-2) + (2(-2) + 1)} ?= (-2) - 1
3{2 + (-4 + 1)} ?= -3
3{2 + (-3)} ?= -3
3{-1} ?= -3
-3 == -3
Thus, we have found the solution for x to be equivalent to negative 2.
Cheers.
Answer:
x = 62
Step-by-step explanation:
62 and x are alternate exterior angles and alternate exterior angles are equal when the lines are parallel
Answer:
Number of cheaper dresses sold is 35
Number of expensive dresses sold is 15
Step-by-step explanation:
Given:
Cost of cheaper dresses = $90
Cost of expensive dresses = $140
Total cost of the dresses = $5250
To Find:
Number of cheaper dress = ?
Number of expensive dress = ?
Solution:
Let
The number of cheaper dresses be x
The number of expensive dresses be y
(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250
= $5250
It is given that the 20 more of the cheaper dresses than the expensive dresses is sold
So,
number of cheaper dress = 20 + number of expensive dress
x = 20 + y---------------------------------------(1)







y = 15
Substituting y in (1)
x = 20 +15
x= 35
Rounded to the nearest tenth the number doesn't change Fam <span />
Answer:
D) q + d = 330
0.25q + 0.1d = 6
Step-by-step explanation:
Let q= numbers of quarters
d = number of dimes
q + d = 33 ...........(1)
q = 33 - d
xq + yd = 6 ..........(2)
We will consider the options to know the correct answer
From option A
q +d = 6
25q + 10d = 33
This is wrong
Option B
q + d = 60
0.25q + 0.1d = 33
This is also wrong
Option C
q+d = 33
25q + 10d = 6
Put q = 33 -d in equation 2
25(33 - d) + 10q = 6
825 - 25d + 10d = 6
825 - 15d = 6
-15d = 6-825
-15d = -819
d = -819/-15
d= 54.6
This is also wrong because d exceeds the combination.
Option D
q+d = 33
0.25q + 0.1d = 6
Put q = 33 -d in equation 2
0.25(33 - d) + 0.1d = 6
8.25 - 0.25d + 0.1d = 6
8.25 - 0.15d = 6
-0.15d = 6 - 8.25
-0.15d = -2.25
d = -2.25/ -0.15
d = 15
q = 33 - 15
q = 18
This is correct