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Sholpan [36]
3 years ago
5

Name a point coplanar to point K.​

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

Point N

Step-by-step explanation:

According to Euclidean geometry, two points are coplanar when they are in the same line segment. By this approach, it is clear that points K and N are part of the same line segment and, consequently, point N is coplanar to point K.

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Solve the following equation show your work 3{-x + (2x + 1)} = x - 1
Reika [66]

Answer:

x = -2

Step-by-step explanation:

For this problem, we must simply solve for x.  To do this, we will need equation operations, and the use of the distributive property.

Let's work this line by line until we have the value for x:

3{-x + (2x + 1)} = x - 1

3*-x + 3*(2x + 1) = x - 1

-3x + 6x + 3 = x - 1

3x + 3 = x - 1

2x = -4

x = -2

Now we can check our answer for x by plugging back into the original equation and see if the left hand side is equal to the right hand side:

3{-x + (2x + 1)} = x - 1

3{-(-2) + (2(-2) + 1)} ?= (-2) - 1

3{2 + (-4 + 1)} ?= -3

3{2 + (-3)} ?= -3

3{-1} ?= -3

-3 == -3

Thus, we have found the solution for x to be equivalent to negative 2.

Cheers.

4 0
3 years ago
Read 2 more answers
Given m n, find the value of X.
Brut [27]

Answer:

x = 62

Step-by-step explanation:

62 and x are alternate exterior angles and alternate exterior angles are equal when the lines are parallel

7 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
3 years ago
344531 to the nearest tenth
sineoko [7]
Rounded to the nearest tenth the number doesn't change Fam <span />
4 0
3 years ago
Martin has a combination of 33 quarters and dimes worth a total of $6. Which system of linear equations can be used to find the
Komok [63]

Answer:

D) q + d = 330

0.25q + 0.1d = 6

Step-by-step explanation:

Let q= numbers of quarters

d = number of dimes

q + d = 33 ...........(1)

q = 33 - d

xq + yd = 6 ..........(2)

We will consider the options to know the correct answer

From option A

q +d = 6

25q + 10d = 33

This is wrong

Option B

q + d = 60

0.25q + 0.1d = 33

This is also wrong

Option C

q+d = 33

25q + 10d = 6

Put q = 33 -d in equation 2

25(33 - d) + 10q = 6

825 - 25d + 10d = 6

825 - 15d = 6

-15d = 6-825

-15d = -819

d = -819/-15

d= 54.6

This is also wrong because d exceeds the combination.

Option D

q+d = 33

0.25q + 0.1d = 6

Put q = 33 -d in equation 2

0.25(33 - d) + 0.1d = 6

8.25 - 0.25d + 0.1d = 6

8.25 - 0.15d = 6

-0.15d = 6 - 8.25

-0.15d = -2.25

d = -2.25/ -0.15

d = 15

q = 33 - 15

q = 18

This is correct

5 0
3 years ago
Read 2 more answers
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