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sdas [7]
3 years ago
12

Which literary device portrays a character's reflections?

Physics
1 answer:
DochEvi [55]3 years ago
6 0
Of the literary devices you provided to choose from, snap hots and thought shots are not even devices so they fall off the list.

sensory language can explain the senses the character is using - helping figure out his reflections,

but figuratve language can helop the best. the character says something figuratively and we can analyze what they meant to find out what they were thinking
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Una persona tiene 45 años de edad y una masa de 78 kg. ¿Cuántas horas ha vivido? ¿Cuál
Pavel [41]

Answer:

I will answer this in English.

He has 45 years.

a year has 365 days.

a day has 24 hours.

So he has:

45*365*24  hours = 394,200 hours.

His mass is 78 kg,

And we know that 1 slug = 1lbf*ft/s^2

Then, the first step is transform the 78 kg into lbf.

1kg = 2.2 lbf.

then 78kg = 78*2.2 lbf = 171.6lbf.

Now, the weight is m*g, where m is the mass and g is the gravitational acceleration, in this case the gravitational acceleration in ft/s^2 is:

g =  32.2 ft/s^2

Then the weight in slugs is:

W = 32.2ft/s^2*171.6lbf = 5,525.5 slugs

8 0
3 years ago
Lenses are described as convergent or divergent depending on how they refract light. What is the difference between these two ty
Umnica [9.8K]

Answer:

Explanation:

Convergent lens is the lens which converges the rays of light falling on it. It is thicker at the middle and thinner at the edges. It is also known as convex lens.

Divergent lens is the lens which diverge the rays of light falling on it. It is thinner at the middle and thicker at the edges. It is also called as concave lens.

5 0
3 years ago
You throw a ball straight up. The ball has an initial speed of 11.2 m/s when it leaves your hand What is the maximum height the
Jet001 [13]

Answer:

Explanation:

Given

initial velocity u=11.2\ m/s

At maximum height velocity of ball is zero

using

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)^2 -(11.2)^2=2\times (-9.8)\times (s)

s=\frac{11.2^2}{2\times 9.8}

s=6.4

time taken by the ball to reach the maximum height

v=u+at

0=11.2-9.8\times t

t=\frac{11.2}{9.8}

t=1.142\ s

At t=2\ s height of ball is

h=ut+\\frac{1}{2}at^2

h=11.2\times 2-\frac{1}{2}9.8\times (2)^2

h=22.4-19.6

h=2.8\ m

i.e. ball is moving downward

height at v=5\ m/s

v^2-u^2=2as

s=\frac{25-125.4}{2\times (-9.8)}

s=5.12\ m    

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