Answer:
The peak emf of the generator is 40.94 V.
Explanation:
Given that,
Number of turns in primary coil= 11
Number of turns in secondary coil= 18
Peak voltage = 67 V
We nee to calculate the peak emf
Using relation of number of turns and emf


Where, N₁ = Number of turns in primary coil
N₂ = Number of turns in secondary coil
E₂ = emf across secondary coil
Put the value into the formula


Hence, The peak emf of the generator is 40.94 V.
Answer: 27.21 V
Explanation:
The <u>electric potential</u>
due to a point charge is expressed as:

Where:
is the <u>electric constant</u>
is the <u>electric charge of the hydrogen nucleus</u>, which is positive
is the <u>distance</u>
Rewritting the equation with the known values:

Finally:
Answer:
x=0.53
Explanation:
Using Gauss law the field is uniform so
E=ζ/ε
Charge densities ⇒ζ=1.
ε=8.85

Force of charge is


So finally knowing the acceleration and the time the distance can be find using equation of uniform motion

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